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πŸ“ Concept diagram

00-01 β€” Whole Number Arithmetic

Phase: 0 β€” Arithmetic & Number Foundations Subject: 00-01 Prerequisites: None (starting point β€” Year 8 level) Next subject: 00-02 β€” Fractions


Learning Objectives

By the end of this subject, you will be able to:

  1. Perform addition, subtraction, multiplication, and division with whole numbers confidently, including with large numbers
  2. Apply the order of operations (PEMDAS/BODMAS) correctly to evaluate multi-step arithmetic expressions
  3. Execute long division and interpret remainders
  4. Identify factors, multiples, primes, and composites, and compute prime factorizations
  5. Find the Greatest Common Factor (GCF) and Least Common Multiple (LCM) of two or more numbers

Core Content

1. Place Value

Every digit in a whole number has a place value determined by its position. Each position is a power of 10:

$... billions  hundred-millions  ten-millions  millions  hundred-thousands  ten-thousands  thousands  hundreds  tens  ones
$

For example, in 73,582:

Digit Place Value
7 ten-thousands 7 Γ— 10,000 = 70,000
3 thousands 3 Γ— 1,000 = 3,000
5 hundreds 5 Γ— 100 = 500
8 tens 8 Γ— 10 = 80
2 ones 2 Γ— 1 = 2

The number is: 70,000 + 3,000 + 500 + 80 + 2 = 73,582.

Place value is why we "carry" in addition and "borrow" in subtraction β€” you're moving values between columns.


2. Addition

Addition combines two or more numbers into a sum.

Algorithm (column addition): 1. Write numbers aligned by place value (units under units, tens under tens, etc.) 2. Add each column from right to left 3. If a column sum is β‰₯ 10, write the units digit and carry the tens digit to the next column

Example: Calculate 4,827 + 3,596

$   ΒΉ ΒΉ ΒΉ     ← carries
   4 8 2 7
+  3 5 9 6
-----------
   8 4 2 3
$

Result: 8,423

Properties of addition: - Commutative: a + b = b + a (order doesn't matter) - Associative: (a + b) + c = a + (b + c) (grouping doesn't matter) - Identity: a + 0 = a (adding zero changes nothing)


3. Subtraction

Subtraction finds the difference between two numbers. Formally: c = a βˆ’ b means b + c = a.

Algorithm (column subtraction with borrowing): 1. Write numbers aligned by place value (larger number on top) 2. Subtract each column from right to left 3. If the top digit is smaller than the bottom digit, borrow from the next left column

Example: Calculate 6,205 βˆ’ 3,847

$   ⁡ ¹¹ ⁹
   6 2 0 5    ← strike through and rewrite after borrowing
βˆ’  3 8 4 7
-----------
   2 3 5 8
$

Let's walk through the borrowing:

Result: 2,358

Check your answer: 2,358 + 3,847 = 6,205 βœ“

Subtraction is not commutative: a βˆ’ b β‰  b βˆ’ a (unless a = b).


4. Multiplication

Multiplication is repeated addition: 5 Γ— 3 = 5 + 5 + 5 = 15.

Algorithm (long multiplication): 1. Write the larger number on top 2. Multiply the top number by each digit of the bottom number, starting from the right 3. Each partial product shifts one place left 4. Add all partial products

Example: Calculate 427 Γ— 358

$        4 2 7
    Γ—   3 5 8
    ---------
      3 4 1 6    ← 427 Γ— 8
    2 1 3 5 0    ← 427 Γ— 5, shifted left 1 place
  1 2 8 1 0 0    ← 427 Γ— 3, shifted left 2 places
  -----------
  1 5 2 8 6 6
$

Step-by-step for the first partial product (427 Γ— 8): - 8 Γ— 7 = 56 β†’ write 6, carry 5 - 8 Γ— 2 + 5 = 16 + 5 = 21 β†’ write 1, carry 2 - 8 Γ— 4 + 2 = 32 + 2 = 34 β†’ write 34 - Partial product: 3,416

Properties of multiplication: - Commutative: a Γ— b = b Γ— a - Associative: (a Γ— b) Γ— c = a Γ— (b Γ— c) - Distributive over addition: a Γ— (b + c) = a Γ— b + a Γ— c - Identity: a Γ— 1 = a - Zero property: a Γ— 0 = 0

⚠️ THIS IS CRITICAL β€” The distributive property is the foundation of all algebra. You will use it thousands of times in later subjects (expanding brackets, factoring, linear algebra). Make sure you understand it deeply now.


5. Division

Division splits a number (the dividend) into equal parts determined by the divisor. The result is the quotient.

Formally: a Γ· b = c means b Γ— c = a. Division is the inverse of multiplication.

If a is not evenly divisible by b, there is a remainder r where 0 ≀ r < b: a = b Γ— q + r (q is quotient, r is remainder)

Algorithm (long division):

Example: Calculate 8,736 Γ· 24

$        3 6 4
      --------
24 ) 8 7 3 6
      7 2       ← 24 Γ— 3 = 72 (how many 24s in 87?)
      ---
      1 5 3     ← bring down 3
      1 4 4     ← 24 Γ— 6 = 144 (how many 24s in 153?)
      -----
          9 6   ← bring down 6
          9 6   ← 24 Γ— 4 = 96 (how many 24s in 96?)
          ---
            0
$

Result: 364 (no remainder)

Algorithm steps: 1. Divide: How many times does the divisor go into the current working digits? 2. Multiply: Multiply the divisor by that digit 3. Subtract: Subtract from the working digits 4. Bring down: Bring down the next digit of the dividend 5. Repeat until all digits are brought down


6. Order of Operations (PEMDAS / BODMAS)

When an expression has multiple operations, you must evaluate them in a specific order:

PEMDAS BODMAS Meaning Priority
P B Parentheses / Brackets 1 (highest)
E O Exponents / Orders 2
MD DM Multiplication & Division 3 (left→right)
AS AS Addition & Subtraction 4 (left→right)

Key rules: - Multiplication and division have equal precedence β€” work from left to right - Addition and subtraction have equal precedence β€” work from left to right - Operations inside parentheses are evaluated first (innermost parentheses first)

Example: Evaluate 10 + 6 Γ— (8 βˆ’ 3)Β² Γ· 5

10 + 6 Γ— (8 βˆ’ 3)Β² Γ· 5
= 10 + 6 Γ— 5Β² Γ· 5         ← Parentheses: (8 βˆ’ 3) = 5
= 10 + 6 Γ— 25 Γ· 5          ← Exponents: 5Β² = 25
= 10 + 150 Γ· 5             ← Multiplication (left): 6 Γ— 25 = 150
= 10 + 30                  ← Division: 150 Γ· 5 = 30
= 40                       ← Addition

Common pitfall: People who ignore order of operations get: 10 + 6 Γ— (8 βˆ’ 3)Β² Γ· 5 β†’ 16 Γ— (5)Β² Γ· 5 β†’ 16 Γ— 25 Γ· 5 β†’ 400 Γ· 5 = 80 (WRONG!)

The mistake was adding 10 + 6 first instead of doing the multiplication first.


7. Factors and Multiples

A factor of a number n is a whole number that divides n exactly (without remainder).

b is a factor of n if n Γ· b has remainder 0.

A multiple of a number n is the product of n and any whole number: n Γ— 1, n Γ— 2, n Γ— 3, ...

m is a multiple of n if m = n Γ— k for some whole number k.

Examples: - Factors of 12: 1, 2, 3, 4, 6, 12 (because 12 Γ· 1, 12 Γ· 2, 12 Γ· 3, 12 Γ· 4, 12 Γ· 6, 12 Γ· 12 all have remainder 0) - Multiples of 7: 7, 14, 21, 28, 35, 42, 49, ...

Relationship: If a is a factor of b, then b is a multiple of a.


8. Prime and Composite Numbers

A prime number is a whole number > 1 that has exactly two factors: 1 and itself.

A composite number is a whole number > 1 that has more than two factors.

The number 1 is neither prime nor composite β€” it has exactly one factor (itself).

⚠️ THIS IS CRITICAL β€” Primes are the building blocks of all whole numbers. Prime factorization appears repeatedly in later subjects including cryptography (RSA), algebraic number theory, and modular arithmetic.

First few primes: 2, 3, 5, 7, 11, 13, 17, 19, 23, 29, 31, 37, 41, 43, 47, ...

Note: 2 is the only even prime β€” every other even number is divisible by 2 and therefore composite.


9. Prime Factorization

Every composite number can be expressed as a unique product of prime numbers. This is the Fundamental Theorem of Arithmetic.

Method (factor tree):

Example: Find the prime factorization of 84

$         84
        /  \
       2   42
          /  \
         2   21
            /  \
           3    7
$

Working from the bottom up: 84 = 2 Γ— 2 Γ— 3 Γ— 7 = 2Β² Γ— 3 Γ— 7

Systematic method: 1. Start with the smallest prime (2). Divide repeatedly while possible. 2. Move to the next prime (3, 5, 7, ...) and repeat. 3. Continue until the result is 1.

$84 Γ· 2 = 42
42 Γ· 2 = 21
21 Γ· 3 = 7
7 Γ· 7 = 1

84 = 2 Γ— 2 Γ— 3 Γ— 7 = 2Β² Γ— 3 Γ— 7
$

10. Greatest Common Factor (GCF)

The GCF (also called GCD β€” Greatest Common Divisor) of two or more numbers is the largest number that divides all of them exactly.

Method using prime factorization: 1. Find the prime factorization of each number 2. For each common prime, take the smallest exponent 3. Multiply these together

Example: Find GCF(48, 180)

48 = 2⁴ Γ— 3
180 = 2Β² Γ— 3Β² Γ— 5

Common primes: 2 and 3
Smallest exponent for 2: 2Β²
Smallest exponent for 3: 3ΒΉ

GCF = 2Β² Γ— 3 = 4 Γ— 3 = 12

Check: 48 Γ· 12 = 4, 180 Γ· 12 = 15 βœ“


11. Least Common Multiple (LCM)

The LCM of two or more numbers is the smallest number that is a multiple of all of them.

Method using prime factorization: 1. Find the prime factorization of each number 2. For each prime that appears, take the largest exponent 3. Multiply these together

Example: Find LCM(48, 180)

48 = 2⁴ Γ— 3
180 = 2Β² Γ— 3Β² Γ— 5

All primes: 2, 3, 5
Largest exponent for 2: 2⁴
Largest exponent for 3: 3Β²
Largest exponent for 5: 5ΒΉ

LCM = 2⁴ Γ— 3Β² Γ— 5 = 16 Γ— 9 Γ— 5 = 720

Check: 720 Γ· 48 = 15, 720 Γ· 180 = 4 βœ“

Important relationship: For any two numbers a and b:

GCF(a,b) Γ— LCM(a,b) = a Γ— b

For 48 and 180: 12 Γ— 720 = 8,640 = 48 Γ— 180 βœ“

This relationship gives you a shortcut: if you've found the GCF, you can get the LCM by dividing the product by the GCF.



Key Terms

Worked Examples

Example 1: Multi-Step Arithmetic with Order of Operations

Evaluate: (24 Γ· 8 + 3Β²) Γ— (15 βˆ’ 7) + 4

Solution:

$(24 Γ· 8 + 3Β²) Γ— (15 βˆ’ 7) + 4
= (24 Γ· 8 + 9) Γ— 8 + 4        ← Exponents (3Β² = 9) and parentheses (15 βˆ’ 7 = 8)
= (3 + 9) Γ— 8 + 4             ← Division inside first parentheses: 24 Γ· 8 = 3
= 12 Γ— 8 + 4                  ← Addition inside parentheses: 3 + 9 = 12
= 96 + 4                      ← Multiplication: 12 Γ— 8 = 96
= 100                         ← Addition
$

Answer: 100


Example 2: Long Division with Remainder

Calculate: 15,283 Γ· 37. Give quotient and remainder.

Solution:

$         4 1 3  r 2
       -------------
37 ) 1 5 2 8 3
      1 4 8         ← 37 Γ— 4 = 148, 152 βˆ’ 148 = 4
      -----
          4 8       ← bring down next digit (8), so we have 48
          3 7       ← 37 Γ— 1 = 37, 48 βˆ’ 37 = 11
          ---
          1 1 3     ← bring down next digit (3), so we have 113
          1 1 1     ← 37 Γ— 3 = 111, 113 βˆ’ 111 = 2
          -----
              2     ← remainder
$

Answer: Quotient = 413, Remainder = 2 Check: 37 Γ— 413 + 2 = 15,281 + 2 = 15,283 βœ“


Example 3: Prime Factorization and GCF/LCM

Find the GCF and LCM of 126 and 294.

Solution:

Step 1 β€” Prime factorization:

$126 Γ· 2 = 63
63 Γ· 3 = 21
21 Γ· 3 = 7
7 Γ· 7 = 1
β†’ 126 = 2 Γ— 3Β² Γ— 7

294 Γ· 2 = 147
147 Γ· 3 = 49
49 Γ· 7 = 7
7 Γ· 7 = 1
β†’ 294 = 2 Γ— 3 Γ— 7Β²
$

Step 2 β€” GCF: Take each common prime with the smallest exponent.

$Common primes: 2ΒΉ, 3ΒΉ, 7ΒΉ
GCF = 2 Γ— 3 Γ— 7 = 42
$

Step 3 β€” LCM: Take all primes with the largest exponent.

$2ΒΉ, 3Β², 7Β²
LCM = 2 Γ— 9 Γ— 49 = 882
$

Verification: 42 Γ— 882 = 37,044 = 126 Γ— 294 βœ“

Answer: GCF = 42, LCM = 882


Practice Problems

(Answers are below. Try each problem before checking.)

Problem 1: Calculate 53,891 + 27,406

Problem 2: Calculate 80,003 βˆ’ 46,789

Problem 3: Calculate 6,248 Γ— 507

Problem 4: Calculate 45,932 Γ· 26. Give quotient and remainder.

Problem 5: Evaluate: 36 Γ· (11 βˆ’ 2) Γ— 2 + 5Β² βˆ’ 3 Γ— 4

Problem 6: Find the prime factorization of 360.

Problem 7: Find the GCF and LCM of 84 and 120.

Answers (click to expand) **Problem 1:** 53,891 + 27,406 = **81,297** **Problem 2:** 80,003 βˆ’ 46,789 = **33,214** **Problem 3:** 6,248 Γ— 507 = **3,167,736** **Problem 4:** 45,932 Γ· 26 = **1,766 remainder 16** Check: 26 Γ— 1,766 + 16 = 45,932 **Problem 5:** 36 Γ· (11 βˆ’ 2) Γ— 2 + 5Β² βˆ’ 3 Γ— 4 = 36 Γ· 9 Γ— 2 + 25 βˆ’ 12 = 4 Γ— 2 + 25 βˆ’ 12 = 8 + 25 βˆ’ 12 = **21** **Problem 6:** 360 = 2 Γ— 2 Γ— 2 Γ— 3 Γ— 3 Γ— 5 = **2Β³ Γ— 3Β² Γ— 5** **Problem 7:** 84 = 2Β² Γ— 3 Γ— 7, 120 = 2Β³ Γ— 3 Γ— 5 GCF = 2Β² Γ— 3 = **12** LCM = 2Β³ Γ— 3 Γ— 5 Γ— 7 = **840**

Summary

  1. Place value is the foundation of all arithmetic β€” each digit represents a power of 10
  2. Addition and subtraction use column alignment with carrying and borrowing
  3. Multiplication uses partial products shifted by place value; the distributive property ⚠️ (a Γ— (b + c) = a Γ— b + a Γ— c) is essential for all algebra
  4. Division is the inverse of multiplication; long division handles large numbers systematically
  5. Order of operations (PEMDAS/BODMAS) determines evaluation order: Parentheses → Exponents → Multiplication/Division (L→R) → Addition/Subtraction (L→R)
  6. Prime numbers β‰₯ 2 with exactly two factors are the building blocks of all whole numbers β€” every composite has a unique prime factorization
  7. GCF uses the smallest exponents of common primes; LCM uses the largest exponents of all primes; GCF Γ— LCM = a Γ— b

Pitfalls


Quiz

Answer each question, then read the explanation for your choice.

Q1: Evaluate: 8 + 2 Γ— (7 βˆ’ 3)Β²

A) 24 B) 40 C) 72 D) 160

Answer and Explanations **Correct: B) 40** 8 + 2 Γ— (7 βˆ’ 3)Β² = 8 + 2 Γ— 4Β² = 8 + 2 Γ— 16 = 8 + 32 = 40 - A) 24: You may have subtracted 3 from 2 instead of following PEMDAS. The Γ— has higher priority than +. - B) 40: βœ“ Correct. Parentheses first (7βˆ’3 = 4), exponent (4Β² = 16), multiply (2 Γ— 16 = 32), add (8 + 32 = 40). - C) 72: You may have done 8 + 2 = 10 first, then 10 Γ— 16 = 160, then... This breaks PEMDAS β€” multiplication comes before addition. - D) 160: You may have evaluated left to right ignoring PEMDAS: (8+2) Γ— (7βˆ’3)Β² = 10 Γ— 16 = 160.

Q2: What is 10,005 βˆ’ 4,837?

A) 5,168 B) 6,168 C) 5,178 D) 6,178

Answer and Explanations **Correct: A) 5,168** 10,005 βˆ’ 4,837 = 5,168. Requires borrowing across zeros: borrow from thousands β†’ hundreds β†’ tens, changing 10,005 into 9,99(15) for subtraction. - A) 5,168: βœ“ Correct. Proper borrowing across zeros. - B) 6,168: You may have borrowed incorrectly, reducing the thousands digit to 6 instead of subtracting 4 from 9. - C) 5,178: Close β€” you may have made an error in the tens column (15βˆ’3 = 12, but the borrowed tens was 9, so 9βˆ’3 = 6). - D) 6,178: Likely the result of not borrowing at all, just subtracting each column individually (10βˆ’4 = 6, 0βˆ’8 = can't = βˆ’8 β†’ wrong).

Q3: What is the prime factorization of 180, expressed with exponents?

A) 2 Γ— 2 Γ— 3 Γ— 3 Γ— 5 B) 2Β² Γ— 3 Γ— 5Β² C) 2Β² Γ— 3Β² Γ— 5 D) 2 Γ— 3Β² Γ— 10

Answer and Explanations **Correct: C) 2Β² Γ— 3Β² Γ— 5** 180 Γ· 2 = 90, 90 Γ· 2 = 45, 45 Γ· 3 = 15, 15 Γ· 3 = 5, 5 Γ· 5 = 1 β†’ 180 = 2Β² Γ— 3Β² Γ— 5 - A) 2 Γ— 2 Γ— 3 Γ— 3 Γ— 5 = 180 βœ“ This IS a prime factorization but it uses repeated multiplication instead of exponents β€” the question asked for exponent form. - B) 2Β² Γ— 3 Γ— 5Β² = 4 Γ— 3 Γ— 25 = 300 βœ—. You have the wrong exponent on 3 and 5. - C) 2Β² Γ— 3Β² Γ— 5 = 4 Γ— 9 Γ— 5 = 180 βœ“ Correct, with exponents. - D) 2 Γ— 3Β² Γ— 10 = 2 Γ— 9 Γ— 10 = 180 βœ“ Equals 180 but 10 is not prime β€” prime factorization requires only prime factors.

Q4: Find the GCF of 72 and 108.

A) 12 B) 18 C) 24 D) 36

Answer and Explanations **Correct: D) 36** 72 = 2Β³ Γ— 3Β², 108 = 2Β² Γ— 3Β³ Common primes: 2 (min exponent 2Β²) and 3 (min exponent 3Β²) GCF = 2Β² Γ— 3Β² = 4 Γ— 9 = 36 - A) 12: 12 divides both but is not the GREATEST common factor. - B) 18: 18 divides both but 36 is larger and also divides both. - C) 24: 24 does NOT divide 108 evenly (108 Γ· 24 = 4.5). - D) 36: βœ“ Correct. 72 Γ· 36 = 2, 108 Γ· 36 = 3, and no larger number divides both.

Q5: What is the LCM of 24 and 36?

A) 36 B) 72 C) 144 D) 864

Answer and Explanations **Correct: B) 72** 24 = 2Β³ Γ— 3, 36 = 2Β² Γ— 3Β² Take largest exponents: 2Β³ Γ— 3Β² = 8 Γ— 9 = 72 - A) 36: 36 is not a multiple of 24 (24 doesn't divide into 36 evenly). - B) 72: βœ“ Correct. 72 Γ· 24 = 3, 72 Γ· 36 = 2. The smallest number divisible by both. - C) 144: 144 is a common multiple but not the LEAST common multiple (72 is smaller). - D) 864: 864 = 24 Γ— 36. This is the product, which equals GCF Γ— LCM = 12 Γ— 72 = 864. But the actual LCM is 72.

Q6: When performing the division 53,742 Γ· 39, what is the quotient and remainder?

A) 1,378 remainder 0 B) 1,377 remainder 39 C) 1,378 remainder 20 D) 1,377 remainder 21

Answer and Explanations **Correct: A) 1,378 remainder 0** 39 Γ— 1,377 = 39 Γ— 1,000 + 39 Γ— 300 + 39 Γ— 70 + 39 Γ— 7 = 39,000 + 11,700 + 2,730 + 273 = 53,703 53,742 βˆ’ 53,703 = 39 So 39 goes into the remainder one more time: 39 Γ— 1,378 = 39 Γ— 1,377 + 39 = 53,703 + 39 = 53,742 exactly. The quotient is 1,378 with remainder 0. - A) 1,378 remainder 0: βœ“ Correct. 39 Γ— 1,378 = 53,742 exactly β€” the division is exact. - B) 1,377 remainder 39: The remainder equals the divisor (39) β€” this should wrap to the next quotient value. 1,377 R 39 is equivalent to 1,378 R 0. - C) 1,378 remainder 20: 39 Γ— 1,378 + 20 = 53,762 β‰  53,742. The remainder is wrong. - D) 1,377 remainder 21: 39 Γ— 1,377 + 21 = 53,724 β‰  53,742. Both quotient and remainder are wrong.

Q7: Which of the following is a prime number?

A) 51 B) 57 C) 61 D) 87

Answer and Explanations **Correct: C) 61** Prime means exactly two factors (1 and itself). - A) 51 = 3 Γ— 17. Composite β€” both 3 and 17 are factors besides 1 and 51. - B) 57 = 3 Γ— 19. Composite β€” 3 Γ— 19 disproves primality. Common trap: 57 looks prime at first glance. - C) 61: βœ“ Prime. It is not divisible by 2, 3, 5, 7 (√61 β‰ˆ 7.8, so you only need to check primes up to 7). - D) 87 = 3 Γ— 29. Composite β€” 8 + 7 = 15 which is divisible by 3, so 87 is divisible by 3.

Q8: Evaluate: (40 Γ· 5 + 2Β³) Γ— (6 βˆ’ 1) + 10 Γ· 2

A) 40 B) 45 C) 85 D) 50

Answer and Explanations **Correct: C) 85** (40 Γ· 5 + 2Β³) Γ— (6 βˆ’ 1) + 10 Γ· 2 = (8 + 8) Γ— 5 + 5 = 16 Γ— 5 + 5 = 80 + 5 = 85 - A) 40: You may have gotten confused by the operations β€” re-check the order. - B) 45: You may have done 16 Γ— 5 = 80 then incorrectly subtracted or mis-handled the + 10 Γ· 2. - C) 85: βœ“ Correct. All steps followed PEMDAS. - D) 50: You may have added before multiplying: (8+8) = 16, but then 16 Γ— (5+5) = 16 Γ— 10 = 160 β†’ wrong. PEMDAS requires multiplication before the final addition.

Next Steps

Move on to 00-02 β€” Fractions to learn about proper/improper fractions, equivalent fractions, simplifying, and fraction operations.




Q5: Which of the following numbers is prime?

A) 51 B) 57 C) 61 D) 87

Answer: C) 61

51 = 3 Γ— 17, 57 = 3 Γ— 19, 87 = 3 Γ— 29. 61 is not divisible by any prime ≀ √61 β‰ˆ 7.8 (tested 2, 3, 5, 7 β€” none divide 61).