01-03 - Linear Inequalities

Phase: 1 | Subject: 01-03 Prerequisites: 01-02-linear-equations.md (solving linear equations) Next subject: 01-04-coordinate-geometry-2d.md


Learning Objectives

By the end of this subject, you will be able to:

  1. Interpret and write inequalities using correct notation (<, >, ≤, ≥)
  2. Represent inequalities on a number line
  3. Solve linear inequalities using the same techniques as equations
  4. Handle the sign-flip rule when multiplying or dividing by a negative
  5. Solve compound inequalities and express answers in interval notation

Core Content

Inequality Notation

Symbol Meaning Example
< less than x < 5 means x is strictly less than 5
> greater than x > 3 means x is strictly greater than 3
$≤$ less than or equal to $x ≤ 2$ includes 2 itself
$≥$ greater than or equal to $x ≥ -1$ includes -1 itself

Key difference from equations: Inequalities have a RANGE of solutions, not a single value.

Number Line Representation

$x < 3      x > -2      x ≤ 5      x ≥ -1
---o======  ====o----  ----[====  ====]----
  0          -2  0  5    0
$

Solving Linear Inequalities

The process is IDENTICAL to solving equations, with ONE critical exception.

Example: $2x + 5 > 11$

  1. Subtract 5: 2x > 6
  2. Divide by 2: x > 3

Check: Try x = 4: $2(4) + 5 = 13 > 11$ ✓ Try x = 2: $2(2) + 5 = 9 > 11$ ✗ (9 is NOT greater than 11)

The Sign-Flip Rule

CRITICAL: When you multiply or divide BOTH SIDES by a NEGATIVE number, you MUST flip the inequality sign.

Why? Think about 3 > 1. If we multiply both sides by -1: - Incorrect: $-3 > -1$ (FALSE - on the number line, -3 is to the LEFT of -1) - Correct: $-3 < -1$ (TRUE - the order reverses when we reflect through 0)

Example: $-2x > 8$

  1. Divide by -2 (NEGATIVE!)
  2. FLIP the sign: $x < -4$

Check: Try x = -5: $-2(-5) = 10 > 8$ ✓ Try x = -3: $-2(-3) = 6 > 8$ ✗

Compound Inequalities

"And" inequalities (intersection)

$-2 < x ≤ 5$ means x must satisfy BOTH conditions. On a number line: open circle at -2, closed circle at 5, shaded between.

Example: Solve $1 < 2x + 3 ≤ 9$

  1. Subtract 3 everywhere: $-2 < 2x ≤ 6$
  2. Divide by 2: $-1 < x ≤ 3$

"Or" inequalities (union)

$x < -2 OR x > 5$ means x satisfies EITHER condition. On a number line: shaded left of -2 AND shaded right of 5.

Interval Notation

A compact way to write solution sets:

Inequality Interval Notation Number Line
x > 3 $(3, ∞)$ Open at 3, arrow right
$x ≥ 3$ $[3, ∞)$ Closed at 3, arrow right
$x < -1$ $(-∞, -1)$ Arrow left, open at -1
$x ≤ -1$ $(-∞, -1]$ Arrow left, closed at -1
$-2 < x ≤ 5$ $(-2, 5]$ Open at -2, closed at 5

Parentheses () = not included Square brackets [] = included Always use ∞ with parentheses (you can't "reach" infinity)



Key Terms

Worked Examples

Example 1: Solve 3x - 7 ≥ 2x + 5

  1. Move x terms to left: $3x - 2x - 7 ≥ 5$
  2. Simplify: $x - 7 ≥ 5$
  3. Add 7: $x ≥ 12$

In interval notation: $[12, ∞)$

Check: x = 12: $3(12) - 7 = 36 - 7 = 29$ and $2(12) + 5 = 24 + 5 = 29$ ✓ x = 13: $3(13) - 7 = 39 - 7 = 32$ and $2(13) + 5 = 26 + 5 = 31$. $32 ≥ 31$ ✓

Example 2: Solve -4x + 3 < 11

  1. Subtract 3: $-4x < 8$
  2. Divide by -4 (NEGATIVE - FLIP!): $x > -2$

In interval notation: $(-2, ∞)$

Check: x = 0: $-4(0) + 3 = 3 < 11$ ✓ x = -3: $-4(-3) + 3 = 12 + 3 = 15 < 11$ ✗ (correctly excluded)

Example 3: Solve -3 ≤ 2x - 5 < 7

  1. Add 5 everywhere: $2 ≤ 2x < 12$
  2. Divide by 2: $1 ≤ x < 6$

In interval notation: [1, 6)

Check: x = 1: $-3 ≤ 2(1) - 5 = -3 < 7$ ✓ x = 6: $-3 ≤ 2(6) - 5 = 7 < 7$ ✗ (7 is not less than 7, correctly excluded)



Quiz

Q1: What does the concept of Compound Inequalities primarily refer to in this subject?

A) A visual representation of Compound Inequalities B) A computational error related to Compound Inequalities C) A historical anecdote about Compound Inequalities D) The definition and application of Compound Inequalities

Correct: D)

Q2: What is the primary purpose of Inequality?

A) It is primarily a historical notation system B) It is used to inequality in mathematical analysis C) It is used only in advanced research contexts D) It replaces all other methods in this domain

Correct: B)

Q3: Which statement about Inequality Notation is TRUE?

A) Inequality Notation is an advanced topic beyond this subject's scope B) Inequality Notation is mentioned only as a historical footnote C) Inequality Notation is a fundamental concept covered in this subject D) Inequality Notation is not related to this subject

Correct: C)

Q4: Based on the worked examples in this subject, what is the correct result?

A) The inverse of the correct answer B) An unrelated numerical value C) A different result from a common mistake D) ** Inequalities have a RANGE of solutions, not a s

Correct: D)

Q5: How are Inequality Notation and Number Line Representation related?

A) Inequality Notation and Number Line Representation are completely unrelated topics B) Inequality Notation is the inverse of Number Line Representation C) Inequality Notation is a special case of Number Line Representation D) Inequality Notation and Number Line Representation are closely related concepts

Correct: D)

Q6: What is a common pitfall when working with Solving Linear Inequalities?

A) A common mistake is confusing Solving Linear Inequalities with a similar concept B) Solving Linear Inequalities is always computed the same way in all contexts C) The main error with Solving Linear Inequalities is using it when it is not needed D) Solving Linear Inequalities has no common misconceptions

Correct: A)

Q7: When should you apply The Sign-Flip Rule?

A) The Sign-Flip Rule is not practically useful B) Apply The Sign-Flip Rule to solve problems in this subject's domain C) Avoid The Sign-Flip Rule unless explicitly instructed D) Use The Sign-Flip Rule only in pure mathematics contexts

Correct: B)

Practice Problems

  1. Solve: $x - 4 > 9$
    Click for answer

x > 13, or $(13, ∞)$

  1. Solve: $5 - 2x ≤ 11$
    Click for answer

$-2x ≤ 6$, divide by -2 (flip!): $x ≥ -3$, or $[-3, ∞)$

  1. Solve: $3x + 2 ≥ 5x - 4$
    Click for answer

$4 ≥ 2x$, so $2 ≥ x$, or $x ≤ 2$, or $(-∞, 2]$

  1. Solve: $-x + 3 < 7$
    Click for answer

$-x < 4$, multiply by -1 (flip!): $x > -4$, or $(-4, ∞)$

  1. Solve: $-2 ≤ 3x + 1 < 10$
    Click for answer

$-3 ≤ 3x < 9$, so $-1 ≤ x < 3$, or $[-1, 3)$

  1. Solve: $(x + 1)/4 ≥ (x - 2)/3$
    Click for answer

Cross multiply (3 > 0, no flip): $3(x + 1) ≥ 4(x - 2)$, $3x + 3 ≥ 4x - 8$, $11 ≥ x$, or $x ≤ 11$

  1. Which values satisfy $-3 < 2x - 1 ≤ 5$?
    Click for answer

$-2 < 2x ≤ 6$, so $-1 < x ≤ 3$, or $(-1, 3]$


Summary

Key takeaways:


Pitfalls



Next Steps

Next up: 01-04-coordinate-geometry-2d.md