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01-09 - Polynomials

Phase: 1 | Subject: 01-09 Prerequisites: 01-08-quadratic-equations.md (quadratic factorising), 01-07-quadratic-expressions.md (expanding brackets) Next subject: 01-10-exponentials-and-logarithms.md


Learning Objectives

By the end of this subject, you will be able to:

  1. Understand polynomial terminology (degree, coefficient, term)
  2. Add and subtract polynomials
  3. Multiply polynomials including special products
  4. Perform polynomial long division
  5. Apply the Remainder Theorem and Factor Theorem

Core Content

Polynomial Terminology

A polynomial is a sum of terms, each being a constant times a variable raised to a non-negative integer power.

Example: 3x⁴ - 2x² + 5x - 7

Term Coefficient Variable part Degree
3x⁴ 3 x⁴ 4
-2x² -2 2
5x 5 x 1
-7 -7 (constant) 0

Adding and Subtracting Polynomials

Combine LIKE TERMS only.

Common pitfall — sign errors in subtraction: When subtracting polynomials, the minus sign applies to EVERY term in the second polynomial. For example: (3x² + 2x) - (x² - 3x) = 3x² + 2x - x² + 3x, NOT 3x² + 2x - x² - 3x. Think of it as adding the negative: (3x² + 2x) + (-x² + 3x).

Example: (3x² + 2x - 5) + (x² - 3x + 4) = (3x² + x²) + (2x - 3x) + (-5 + 4) = 4x² - x - 1

Example: (2x³ + 4x - 1) - (x³ - 2x + 3) = 2x³ - x³ + 4x + 2x - 1 - 3 = x³ + 6x - 4

Multiplying Polynomials

Use the distributive law (FOIL for binomials).

Example: (x + 3)(x² - 2x + 1) = x(x² - 2x + 1) + 3(x² - 2x + 1) = x³ - 2x² + x + 3x² - 6x + 3 = x³ + x² - 5x + 3

Special Products

(a + b)(a - b) = a² - b² (Difference of squares)

(a + b)² = a² + 2ab + b² (Perfect square)

(a - b)² = a² - 2ab + b² (Perfect square)

Example: (2x + 5)² = 4x² + 20x + 25

Example: (3x - 4)(3x + 4) = 9x² - 16

Polynomial Long Division

Divide polynomials like long division with numbers.

Example: Divide 2x³ + 3x² - x + 5 by x + 1

  1. 2x³ ÷ x = 2x². Multiply: 2x²(x + 1) = 2x³ + 2x²
  2. Subtract: (2x³ + 3x²) - (2x³ + 2x²) = x²
  3. Bring down -x: x² - x
  4. x² ÷ x = x. Multiply: x(x + 1) = x² + x
  5. Subtract: (x² - x) - (x² + x) = -2x
  6. Bring down 5: -2x + 5
  7. -2x ÷ x = -2. Multiply: -2(x + 1) = -2x - 2
  8. Subtract: (-2x + 5) - (-2x - 2) = 7

Result: 2x³ + 3x² - x + 5 = (x + 1)(2x² + x - 2) + 7

Quotient: 2x² + x - 2, Remainder: 7

Remainder Theorem

When P(x) is divided by (x - a), the remainder is P(a).

Example: Remainder when x³ - 2x² + 4 is divided by (x - 3)? P(3) = 27 - 18 + 4 = 13. Remainder is 13.

Factor Theorem

(x - a) is a factor of P(x) if and only if P(a) = 0.

Example: Is (x - 2) a factor of x³ - 3x² + 4? P(2) = 8 - 12 + 4 = 0. YES, (x - 2) is a factor.



Key Terms

Worked Examples

Example 1: Expand and simplify

(2x - 3)(x² + x - 1) = 2x³ + 2x² - 2x - 3x² - 3x + 3 = 2x³ - x² - 5x + 3

Example 2: Polynomial division

Divide x³ + 2x² - 5x + 3 by x - 2.

  1. x³ ÷ x = x². Multiply: x²(x - 2) = x³ - 2x²
  2. Subtract: (x³ + 2x²) - (x³ - 2x²) = 4x²
  3. Bring down -5x: 4x² - 5x
  4. 4x² ÷ x = 4x. Multiply: 4x(x - 2) = 4x² - 8x
  5. Subtract: (4x² - 5x) - (4x² - 8x) = 3x
  6. Bring down 3: 3x + 3
  7. 3x ÷ x = 3. Multiply: 3(x - 2) = 3x - 6
  8. Subtract: (3x + 3) - (3x - 6) = 9

Result: x³ + 2x² - 5x + 3 = (x - 2)(x² + 4x + 3) + 9

Example 3: Using the Factor Theorem

Determine whether (x + 2) is a factor of P(x) = x³ + 3x² - 4x - 12, and factorise completely if possible.

  1. Check if P(-2) = 0: P(-2) = (-2)³ + 3(-2)² - 4(-2) - 12
  2. = -8 + 3(4) + 8 - 12
  3. = -8 + 12 + 8 - 12 = 0 ✓
  4. Since P(-2) = 0, (x + 2) is a factor by the Factor Theorem.
  5. Divide P(x) by (x + 2) to find the other factor:
  6. x³ ÷ x = x². Multiply: x²(x + 2) = x³ + 2x²
  7. Subtract: (x³ + 3x²) - (x³ + 2x²) = x²
  8. Bring down -4x: x² - 4x
  9. x² ÷ x = x. Multiply: x(x + 2) = x² + 2x
  10. Subtract: (x² - 4x) - (x² + 2x) = -6x
  11. Bring down -12: -6x - 12
  12. -6x ÷ x = -6. Multiply: -6(x + 2) = -6x - 12
  13. Subtract: 0 (remainder 0 confirms factor)
  14. Quotient: x² + x - 6
  15. Factorise the quotient: x² + x - 6 = (x + 3)(x - 2)
  16. Complete factorisation: P(x) = (x + 2)(x + 3)(x - 2)

This shows how the Factor Theorem reduces the work: find one root, divide, then factorise the simpler quotient.



Quiz

Q1: What does the concept of Adding and Subtracting Polynomials primarily refer to in this subject?

A) A historical anecdote about Adding and Subtracting Polynomials B) The definition and application of Adding and Subtracting Polynomials C) A visual representation of Adding and Subtracting Polynomials D) A computational error related to Adding and Subtracting Polynomials

Correct: B)

Q2: What is the primary purpose of Factor Theorem?

A) It is used only in advanced research contexts B) It is used to factor theorem in mathematical analysis C) It replaces all other methods in this domain D) It is primarily a historical notation system

Correct: B)

Q3: Which statement about Polynomial Terminology is TRUE?

A) Polynomial Terminology is not related to this subject B) Polynomial Terminology is mentioned only as a historical footnote C) Polynomial Terminology is an advanced topic beyond this subject's scope D) Polynomial Terminology is a fundamental concept covered in this subject

Correct: D)

Q4: Based on the worked examples in this subject, what is the correct result?

A) The inverse of the correct answer B) An unrelated numerical value C) A different result from a common mistake D) (x + 1)(2x² + x - 2) + 7

Correct: D)

Q5: How are Polynomial Terminology and Multiplying Polynomials related?

A) Polynomial Terminology and Multiplying Polynomials are closely related concepts B) Polynomial Terminology is a special case of Multiplying Polynomials C) Polynomial Terminology is the inverse of Multiplying Polynomials D) Polynomial Terminology and Multiplying Polynomials are completely unrelated topics

Correct: A)

Q6: What is a common pitfall when working with Special Products?

A) Special Products has no common misconceptions B) A common mistake is confusing Special Products with a similar concept C) Special Products is always computed the same way in all contexts D) The main error with Special Products is using it when it is not needed

Correct: B)

Q7: When should you apply Polynomial Long Division?

A) Avoid Polynomial Long Division unless explicitly instructed B) Use Polynomial Long Division only in pure mathematics contexts C) Polynomial Long Division is not practically useful D) Apply Polynomial Long Division to solve problems in this subject's domain

Correct: D)

Practice Problems

  1. Add: (3x² - 2x + 1) + (x² + 4x - 5)
    Click for answer

4x² + 2x - 4

  1. Multiply: (x + 2)(x - 3)
    Click for answer

x² - x - 6

  1. Expand: (2x - 1)²
    Click for answer

4x² - 4x + 1

  1. Divide (x² + 5x + 6) by (x + 2)
    Click for answer

Quotient: x + 3, Remainder: 0. (x + 2) is a factor.

  1. Remainder when P(x) = x³ - 4x + 2 is divided by (x - 1)
    Click for answer

P(1) = 1 - 4 + 2 = -1

  1. Is (x + 3) a factor of x² + 2x - 15?
    Click for answer

P(-3) = 9 - 6 - 15 = -12 ≠ 0. No, not a factor. (x + 5) and (x - 3) are the factors.


Summary

Key takeaways:


Pitfalls



Next Steps

Next up: 01-10-exponentials-and-logarithms.md