Math graphic
📐 Concept diagram

05-01 - Antiderivatives

Phase: 5 | Subject: 05-01 Prerequisites: 04-04-differentiation-rules.md (power rule, derivatives of elementary functions) Next subject: 05-02-the-definite-integral.md


Learning Objectives

By the end of this subject, you will be able to:

  1. Define antiderivatives and understand the relationship to derivatives
  2. Use the power rule for integration
  3. Integrate polynomials
  4. Apply basic integration rules for elementary functions
  5. Understand the constant of integration

Core Content

What is an Antiderivative?

An antiderivative of f(x) is a function F(x) such that F'(x) = f(x).

Example: f(x) = 2x An antiderivative is F(x) = x² because d/dx[x²] = 2x.

But x² + 5, x² - 3, and x² + C (for any constant C) are also antiderivatives!

General form: F(x) + C, where C is any constant.

The Indefinite Integral

The indefinite integral is the set of ALL antiderivatives:

$∫f(x)dx = F(x) + C
$

Key notation: - ∫ is the integral sign (elongated S for "sum") - f(x) is the integrand - dx means "with respect to x" - C is the constant of integration

Basic Integration Rules

Power Rule for Integration

∫xⁿdx = x^(n+1)/(n+1) + C   (for n ≠ -1)

Example: ∫x³dx = x⁴/4 + C Example: ∫x²dx = x³/3 + C Example: ∫x dx = x²/2 + C Example: ∫1 dx = x + C

Special Case: n = -1

∫(1/x)dx = ln|x| + C

This is because d/dx[ln(x)] = 1/x.

Constant Multiple Rule

∫k·f(x)dx = k·∫f(x)dx

Example: ∫3x²dx = 3∫x²dx = 3(x³/3) = x³ + C

Sum/Difference Rule

∫[f(x) ± g(x)]dx = ∫f(x)dx ± ∫g(x)dx

Example: ∫(3x² - 2x + 1)dx = x³ - x² + x + C

Integration of Elementary Functions

$∫eˣdx = eˣ + C
∫aˣdx = aˣ/ln(a) + C
∫sin(x)dx = -cos(x) + C
∫cos(x)dx = sin(x) + C
∫sec²(x)dx = tan(x) + C
∫csc²(x)dx = -cot(x) + C
∫sec(x)tan(x)dx = sec(x) + C
∫csc(x)cot(x)dx = -csc(x) + C
$

Verification: Differentiate the result to check.



Key Terms

The indefinite integral - Integration of Elementary Functions - Power Rule for Integration - Special Case: n = -1**

Worked Examples

Example 1: Polynomial

∫(4x³ - 2x² + 5x - 7)dx = 4(x⁴/4) - 2(x³/3) + 5(x²/2) - 7x + C = x⁴ - (2/3)x³ + (5/2)x² - 7x + C

Example 2: Exponential and trig

∫(eˣ + sin(x) + 3)dx = eˣ - cos(x) + 3x + C

Example 3: With constant multiple

∫(2eˣ - 3cos(x))dx = 2eˣ - 3sin(x) + C


Practice Problems

Problem 1: ∫x⁴dx

Answer x⁵/5 + C

Problem 2: ∫(3x² + 2x)dx

Answer x³ + x² + C

Problem 3: ∫e^(2x)dx

Answer (1/2)e^(2x) + C

Problem 4: ∫cos(3x)dx

Answer (1/3)sin(3x) + C

Problem 5: ∫(1/x)dx

Answer ln|x| + C

Problem 6: ∫(5x³ - 4x + 2)dx

Answer (5/4)x⁴ - 2x² + 2x + C

Summary

Key takeaways:


Pitfalls


Quiz

Q1: ∫x³dx equals:

A) 3x² + C B) x⁴/4 + C C) x² + C D) 4x³ + C

Answer and Explanations **Correct: B)** - If you chose B: Power rule: ∫xⁿdx = x^(n+1)/(n+1). Here n=3: x⁴/4 + C. Correct! - If you chose A: That's the DERIVATIVE of x⁴/4, not the integral. - If you chose C: You divided by 3 instead of 4. n+1 = 3+1 = 4. - If you chose D: That's 4 times x³. Not an antiderivative.

Q2: ∫(2x + 3)dx equals:

A) x² + 3x + C B) 2x² + 3x + C C) x² + 3 + C D) 2x + 3 + C

Answer and Explanations **Correct: A)** - If you chose A: ∫2x dx = x², ∫3 dx = 3x. Sum: x² + 3x + C. Correct! - If you chose B: You forgot to divide by the new power: ∫2x dx = 2(x²/2) = x², not 2x². - If you chose C: You forgot to multiply the constant by x: ∫3 dx = 3x, not 3. - If you chose D: You just added C to the original function. That's not integration.

Q3: ∫eˣdx equals:

A) eˣ + C B) xeˣ + C C) eˣ/x + C D) ln(x) + C

Answer and Explanations **Correct: A)** - If you chose A: eˣ is its own derivative, so it's its own antiderivative. Correct! - If you chose B: That's the integral of something involving product rule, not eˣ. - If you chose C: That's not a standard integral. eˣ/x has no elementary antiderivative. - If you chose D: That's the integral of 1/x, not eˣ.

Q4: ∫(1/x)dx equals:

A) x²/2 + C B) ln|x| + C C) 1/x² + C D) eˣ + C

Answer and Explanations **Correct: B)** - If you chose B: ∫(1/x)dx = ln|x| + C. Correct! - If you chose A: That's ∫x dx. Not 1/x. - If you chose C: That's ∫(-1/x²)dx or -1/x + C. - If you chose D: That's ∫eˣ dx.

Q5: ∫sin(x)dx equals:

A) cos(x) + C B) -cos(x) + C C) -sin(x) + C D) tan(x) + C

Answer and Explanations **Correct: B)** - If you chose B: d/dx[-cos(x)] = sin(x). Correct! - If you chose A: d/dx[cos(x)] = -sin(x). You have the wrong sign. - If you chose C: d/dx[-sin(x)] = -cos(x). That's the integral of -cos(x). - If you chose D: d/dx[tan(x)] = sec²(x). Not related.

Next Steps

Next up: 05-02-the-definite-integral.md