05-01 - Antiderivatives
Phase: 5 | Subject: 05-01 Prerequisites: 04-04-differentiation-rules.md (power rule, derivatives of elementary functions) Next subject: 05-02-the-definite-integral.md
Learning Objectives
By the end of this subject, you will be able to:
- Define antiderivatives and understand the relationship to derivatives
- Use the power rule for integration
- Integrate polynomials
- Apply basic integration rules for elementary functions
- Understand the constant of integration
Core Content
What is an Antiderivative?
An antiderivative of f(x) is a function F(x) such that F'(x) = f(x).
Example: f(x) = 2x An antiderivative is F(x) = x² because d/dx[x²] = 2x.
But x² + 5, x² - 3, and x² + C (for any constant C) are also antiderivatives!
General form: F(x) + C, where C is any constant.
The Indefinite Integral
The indefinite integral is the set of ALL antiderivatives:
$∫f(x)dx = F(x) + C $
Key notation: - ∫ is the integral sign (elongated S for "sum") - f(x) is the integrand - dx means "with respect to x" - C is the constant of integration
Basic Integration Rules
Power Rule for Integration
∫xⁿdx = x^(n+1)/(n+1) + C (for n ≠ -1)
Example: ∫x³dx = x⁴/4 + C Example: ∫x²dx = x³/3 + C Example: ∫x dx = x²/2 + C Example: ∫1 dx = x + C
Special Case: n = -1
∫(1/x)dx = ln|x| + C
This is because d/dx[ln(x)] = 1/x.
Constant Multiple Rule
∫k·f(x)dx = k·∫f(x)dx
Example: ∫3x²dx = 3∫x²dx = 3(x³/3) = x³ + C
Sum/Difference Rule
∫[f(x) ± g(x)]dx = ∫f(x)dx ± ∫g(x)dx
Example: ∫(3x² - 2x + 1)dx = x³ - x² + x + C
Integration of Elementary Functions
$∫eˣdx = eˣ + C ∫aˣdx = aˣ/ln(a) + C ∫sin(x)dx = -cos(x) + C ∫cos(x)dx = sin(x) + C ∫sec²(x)dx = tan(x) + C ∫csc²(x)dx = -cot(x) + C ∫sec(x)tan(x)dx = sec(x) + C ∫csc(x)cot(x)dx = -csc(x) + C $
Verification: Differentiate the result to check.
Key Terms
- 05 01 Antiderivatives
- Basic Integration Rules
- Constant Multiple Rule
- Correct: A)
- Correct: B)
- Example 1: Polynomial
- Example 2: Exponential and trig
- Example 3: With constant multiple
- **Indefinite Integral
The indefinite integral - Integration of Elementary Functions - Power Rule for Integration - Special Case: n = -1**
Worked Examples
Example 1: Polynomial
∫(4x³ - 2x² + 5x - 7)dx = 4(x⁴/4) - 2(x³/3) + 5(x²/2) - 7x + C = x⁴ - (2/3)x³ + (5/2)x² - 7x + C
Example 2: Exponential and trig
∫(eˣ + sin(x) + 3)dx = eˣ - cos(x) + 3x + C
Example 3: With constant multiple
∫(2eˣ - 3cos(x))dx = 2eˣ - 3sin(x) + C
Practice Problems
Problem 1: ∫x⁴dx
Answer
x⁵/5 + CProblem 2: ∫(3x² + 2x)dx
Answer
x³ + x² + CProblem 3: ∫e^(2x)dx
Answer
(1/2)e^(2x) + CProblem 4: ∫cos(3x)dx
Answer
(1/3)sin(3x) + CProblem 5: ∫(1/x)dx
Answer
ln|x| + CProblem 6: ∫(5x³ - 4x + 2)dx
Answer
(5/4)x⁴ - 2x² + 2x + CSummary
Key takeaways:
- Antiderivative: F'(x) = f(x)
- ∫f(x)dx = F(x) + C (all antiderivatives)
- Power rule: ∫xⁿdx = x^(n+1)/(n+1) + C
- Special: ∫(1/x)dx = ln|x| + C
- ∫eˣdx = eˣ + C
- ∫sin(x)dx = -cos(x) + C, ∫cos(x)dx = sin(x) + C
- Always include + C for indefinite integrals
Pitfalls
- Forgetting the +C constant of integration. An indefinite integral represents a family of functions. Leaving off +C is technically wrong and will cost you points on exams — it's the most common integration mistake.
- Applying the power rule incorrectly. ∫xⁿdx = x^(n+1)/(n+1) + C, NOT x^(n-1)/n + C. The exponent increases by 1 then divides, the opposite of differentiation where the exponent decreases by 1 then multiplies.
- Treating ∫(1/x)dx as x⁰/0. The power rule has a special exception at n = -1: ∫x⁻¹dx = ln|x| + C, not x⁰/0. This catches many students.
- Mixing up signs on trig integrals. ∫sin(x)dx = -cos(x) + C (negative!), while ∫cos(x)dx = sin(x) + C (positive). It's easy to swap these signs because differentiation does the reverse: cos' = -sin, sin' = cos.
- Forgetting to account for the inner derivative. ∫e^(2x)dx = (1/2)e^(2x) + C, not just e^(2x) + C. When the argument is not just x, integration by substitution is needed to handle the chain factor.
Quiz
Q1: ∫x³dx equals:
A) 3x² + C B) x⁴/4 + C C) x² + C D) 4x³ + C
Answer and Explanations
**Correct: B)** - If you chose B: Power rule: ∫xⁿdx = x^(n+1)/(n+1). Here n=3: x⁴/4 + C. Correct! - If you chose A: That's the DERIVATIVE of x⁴/4, not the integral. - If you chose C: You divided by 3 instead of 4. n+1 = 3+1 = 4. - If you chose D: That's 4 times x³. Not an antiderivative.Q2: ∫(2x + 3)dx equals:
A) x² + 3x + C B) 2x² + 3x + C C) x² + 3 + C D) 2x + 3 + C
Answer and Explanations
**Correct: A)** - If you chose A: ∫2x dx = x², ∫3 dx = 3x. Sum: x² + 3x + C. Correct! - If you chose B: You forgot to divide by the new power: ∫2x dx = 2(x²/2) = x², not 2x². - If you chose C: You forgot to multiply the constant by x: ∫3 dx = 3x, not 3. - If you chose D: You just added C to the original function. That's not integration.Q3: ∫eˣdx equals:
A) eˣ + C B) xeˣ + C C) eˣ/x + C D) ln(x) + C
Answer and Explanations
**Correct: A)** - If you chose A: eˣ is its own derivative, so it's its own antiderivative. Correct! - If you chose B: That's the integral of something involving product rule, not eˣ. - If you chose C: That's not a standard integral. eˣ/x has no elementary antiderivative. - If you chose D: That's the integral of 1/x, not eˣ.Q4: ∫(1/x)dx equals:
A) x²/2 + C B) ln|x| + C C) 1/x² + C D) eˣ + C
Answer and Explanations
**Correct: B)** - If you chose B: ∫(1/x)dx = ln|x| + C. Correct! - If you chose A: That's ∫x dx. Not 1/x. - If you chose C: That's ∫(-1/x²)dx or -1/x + C. - If you chose D: That's ∫eˣ dx.Q5: ∫sin(x)dx equals:
A) cos(x) + C B) -cos(x) + C C) -sin(x) + C D) tan(x) + C
Answer and Explanations
**Correct: B)** - If you chose B: d/dx[-cos(x)] = sin(x). Correct! - If you chose A: d/dx[cos(x)] = -sin(x). You have the wrong sign. - If you chose C: d/dx[-sin(x)] = -cos(x). That's the integral of -cos(x). - If you chose D: d/dx[tan(x)] = sec²(x). Not related.Next Steps
Next up: 05-02-the-definite-integral.md