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02-05 - Pythagoras and Right Triangle Trig

Phase: 2 | Subject: 02-05 Prerequisites: 02-04-perimeter-area-volume.md (area of triangles), 01-04-coordinate-geometry-2d.md (distance formula) Next subject: 02-06-non-right-triangle-trig.md


Learning Objectives

By the end of this subject, you will be able to:

  1. State and apply Pythagoras' theorem
  2. Use Pythagorean triples for quick calculations
  3. Apply 3D Pythagoras in three dimensions
  4. Use sine, cosine, and tangent ratios (SOH CAH TOA)
  5. Solve for missing sides and angles in right triangles
  6. Apply trigonometry to angles of elevation and depression
  7. Understand and calculate bearings

Core Content

Pythagoras' Theorem

⚠️ THIS IS CRITICAL — a² + b² = c² is arguably the most important formula in all of geometry. It appears everywhere: from distance calculations to the unit circle to vector magnitudes to machine learning loss functions.

In any RIGHT-angled triangle:

$a² + b² = c²
$

where c = hypotenuse (longest side, opposite the right angle) and a, b = the two shorter sides (legs)

Why it works: The area of the square on the hypotenuse equals the sum of areas of squares on the other two sides. This can be proven geometrically.

Finding the hypotenuse: $c = √(a² + b²)$

Finding a shorter side: $a = √(c² - b²)$ or $b = √(c² - a²)$

Pythagorean Triples

Integer solutions to a² + b² = c²:

Triple Verification
(3, 4, 5) 9 + 16 = 25
(5, 12, 13) 25 + 144 = 169
(8, 15, 17) 64 + 225 = 289
(7, 24, 25) 49 + 576 = 625

Multiples work too: (6, 8, 10), (9, 12, 15), etc.

3D Pythagoras

For a rectangular box with dimensions a, b, c:

Diagonal from one corner to opposite: d = √(a² + b² + c²)

Example: Box 3m × 4m × 5m d = √(9 + 16 + 25) = √50 = 5√2 ≈ 7.07m

SOH CAH TOA Mnemonic

For a RIGHT triangle with angle θ:

⚠️ THIS IS CRITICAL — SOH CAH TOA is the single most important mnemonic in trigonometry. Memorise it. You will use it in every trig subject from now through calculus and beyond.

$sin(θ) = opposite / hypotenuse  (SOH)
cos(θ) = adjacent / hypotenuse  (CAH)
tan(θ) = opposite / adjacent     (TOA)
$

To remember: - SOH: Sine = Opposite over Hypotenuse - CAH: Cosine = Adjacent over Hypotenuse - TOA: Tangent = Opposite over Adjacent

Finding Missing Sides

If you know an angle and one side, use the trig ratios.

Example: Right triangle with θ = 30°, hypotenuse = 10. Find opposite side.

sin(30°) = opposite / 10 opposite = 10 × sin(30°) = 10 × 0.5 = 5

Finding Missing Angles

Use inverse trig functions: sin⁻¹, cos⁻¹, tan⁻¹

Example: Opposite = 4, adjacent = 3. Find θ.

tan(θ) = 4/3 θ = tan⁻¹(4/3) ≈ 53.13°

When to Use Which Ratio

You know You want Use
Angle + hypotenuse Opposite sin
Angle + hypotenuse Adjacent cos
Angle + opposite Adjacent tan
Angle + adjacent Opposite tan
Opposite + hypotenuse Angle sin⁻¹
Adjacent + hypotenuse Angle cos⁻¹
Opposite + adjacent Angle tan⁻¹

Pitfalls

Angles of Elevation and Depression

Angle of elevation: Looking UP from horizontal to an object Angle of depression: Looking DOWN from horizontal to an object

By parallel line rules, angle of elevation = angle of depression.

Example: Standing 50m from a building. Angle of elevation to top is 35°. Find building height.

tan(35°) = height / 50 height = 50 × tan(35°) ≈ 50 × 0.700 ≈ 35.0m

Bearings

A bearing is a direction measured clockwise from North.

Example: Bearing of 135° is Southeast (halfway between South and East)

Back bearing: Add or subtract 180° (if result > 360°, subtract 360°)

Example: Bearing 045° → back bearing 225° Bearing 300° → back bearing 120° (300 - 180 = 120)



Key Terms

Worked Examples

Example 1: Pythagoras

Right triangle with legs 6cm and 8cm. Find hypotenuse.

c = √(36 + 64) = √100 = 10cm

Recognise this as the (6, 8, 10) triple (multiple of 3-4-5).

Example 2: Trigonometry

Right triangle: angle 40°, adjacent side 12cm. Find opposite.

tan(40°) = opposite / 12 opposite = 12 × tan(40°) ≈ 12 × 0.839 ≈ 10.07cm

Example 3: Angle of depression

From a cliff 80m high, angle of depression to a boat is 25°. Find horizontal distance to boat.

The angle of depression = angle of elevation from boat = 25°. tan(25°) = 80 / distance distance = 80 / tan(25°) ≈ 80 / 0.466 ≈ 171.7m



Quiz

Q1: What does the concept of Angles of Elevation and Depression primarily refer to in this subject?

A) The definition and application of Angles of Elevation and Depression B) A historical anecdote about Angles of Elevation and Depression C) A visual representation of Angles of Elevation and Depression D) A computational error related to Angles of Elevation and Depression

Correct: A)

Q2: What is the primary purpose of Bearings?

A) It is primarily a historical notation system B) It replaces all other methods in this domain C) It is used only in advanced research contexts D) It is used to bearings in mathematical analysis

Correct: D)

Q3: Which statement about Common Pitfalls is TRUE?

A) Common Pitfalls is not related to this subject B) Common Pitfalls is a fundamental concept covered in this subject C) Common Pitfalls is mentioned only as a historical footnote D) Common Pitfalls is an advanced topic beyond this subject's scope

Correct: B)

Q4: Based on the worked examples in this subject, what is the correct result?

A) The inverse of the correct answer B) An unrelated numerical value C) ** Bearing 045° → back bearing 225° D) A different result from a common mistake

Correct: C)

Q5: How are Common Pitfalls and Pythagoras' Theorem related?

A) Common Pitfalls and Pythagoras' Theorem are completely unrelated topics B) Common Pitfalls is a special case of Pythagoras' Theorem C) Common Pitfalls and Pythagoras' Theorem are closely related concepts D) Common Pitfalls is the inverse of Pythagoras' Theorem

Correct: C)

Q6: What is a common pitfall when working with Pythagorean Triples?

A) The main error with Pythagorean Triples is using it when it is not needed B) A common mistake is confusing Pythagorean Triples with a similar concept C) Pythagorean Triples is always computed the same way in all contexts D) Pythagorean Triples has no common misconceptions

Correct: B)

Q7: When should you apply 3D Pythagoras?

A) Use 3D Pythagoras only in pure mathematics contexts B) 3D Pythagoras is not practically useful C) Apply 3D Pythagoras to solve problems in this subject's domain D) Avoid 3D Pythagoras unless explicitly instructed

Correct: C)

Practice Problems

  1. Find hypotenuse of right triangle with legs 5 and 12 Answer: √(25 + 144) = √169 = 13

  2. Find missing side if hypotenuse = 10 and one leg = 6 Answer: √(100 - 36) = √64 = 8

  3. 3D: diagonal of 3×4×12 box Answer: √(9 + 16 + 144) = √169 = 13

  4. Right triangle: angle 45°, hypotenuse 10. Find opposite. Answer: 10 × sin(45°) = 10 × (√2/2) = 5√2 ≈ 7.07

  5. Right triangle: opposite 7, adjacent 24. Find angle. Answer: tan⁻¹(7/24) ≈ 16.26°

  6. Angle of elevation to top of tree (height 15m) from 20m away Answer: tan⁻¹(15/20) = tan⁻¹(0.75) ≈ 36.87°

  7. Bearing 210°. What direction is this? Answer: 210 - 180 = 30° past South, so South 30° West (or just Southwest-ish)


Summary

Key takeaways:



Next Steps

Next up: 02-06-non-right-triangle-trig.md