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📐 Concept diagram

03-05 - Exponential and Logarithmic Functions

Phase: 3 | Subject: 03-05 Prerequisites: 03-04-rational-functions.md (asymptotes, domain), 01-10-exponentials-and-logarithms.md (basic exponent/log rules) Next subject: 03-06-complex-numbers.md


Learning Objectives

By the end of this subject, you will be able to:

  1. Graph exponential functions aˣ and identify key features
  2. Graph logarithmic functions logₐ(x) and identify key features
  3. Apply transformations to exponential and logarithmic graphs
  4. Solve exponential and logarithmic equations
  5. Model exponential growth and decay, including logistic growth

Core Content

Exponential Functions

Form: f(x) = aˣ where a > 0, a ≠ 1

Key features: - Always passes through (0, 1) because a⁰ = 1 - Horizontal asymptote: y = 0 (the x-axis) - Domain: all real numbers - Range: y > 0 - a > 1: growth function (increasing) - 0 < a < 1: decay function (decreasing)

Example: f(x) = 2ˣ f(0) = 1, f(1) = 2, f(2) = 4, f(-1) = 1/2, f(-2) = 1/4

Transformation: y = a·bˣ + k - a: vertical stretch/reflection - b > 1: growth; 0 < b < 1: decay - k: vertical shift

Logarithmic Functions

Form: f(x) = logₐ(x) where a > 0, a ≠ 1

Logarithm is the INVERSE of exponential: y = logₐ(x) means aʸ = x

Key features: - Always passes through (1, 0) because logₐ(1) = 0 - Vertical asymptote: x = 0 (the y-axis) - Domain: x > 0 - Range: all real numbers - a > 1: increasing; 0 < a < 1: decreasing

Example: f(x) = log₂(x) f(1) = 0, f(2) = 1, f(4) = 2, f(1/2) = -1, f(1/4) = -2

Logarithm Laws

$logₐ(xy) = logₐ(x) + logₐ(y)           (product)
logₐ(x/y) = logₐ(x) - logₐ(y)           (quotient)
logₐ(xⁿ) = n·logₐ(x)                    (power)
logₐ(a) = 1                             (identity)
logₐ(1) = 0                             (identity)
logₐ(x) = ln(x) / ln(a)                 (change of base)
a^(logₐ(x)) = x                          (inverse — exponential undoes log)
$

Solving Exponential Equations

Strategy: Get the same base on both sides, then equate exponents.

Example: Solve 3ˣ = 81

3ˣ = 3⁴ x = 4

Example: Solve 2^(2x - 1) = 8

2^(2x - 1) = 2³ 2x - 1 = 3 2x = 4 x = 2

Solving Logarithmic Equations

Strategy: Use log laws to combine or isolate the log, then convert to exponential.

Example: Solve log₂(x) + log₂(x - 3) = 3

  1. Combine: log₂(x(x - 3)) = 3
  2. Exponential: x(x - 3) = 2³ = 8
  3. x² - 3x - 8 = 0
  4. x = (3 ± √(9 + 32))/2 = (3 ± √41)/2
  5. Only positive solution valid (domain x > 0 and x > 3): x = (3 + √41)/2 ≈ 4.7

Exponential Growth and Decay Models

General form: P(t) = P₀·aᵗ

Continuous model: P(t) = P₀·e^(kt) - k > 0: growth - k < 0: decay

Half-life: Time for quantity to halve Doubling time: Time for quantity to double

Example: Radioactive decay with half-life 5 years. P(t) = P₀·(1/2)^(t/5)

Logistic Growth:

$P(t) = L / (1 + Ae^(-kt))
$

where L = carrying capacity (maximum population) Initially exponential, then slows as it approaches L.



Key Terms

Worked Examples

Example 1: Graph transformations

Sketch y = 2·3^(x - 1) + 1

  1. Start with y = 3ˣ (passes through (0, 1), asymptote y = 0)
  2. Shift right 1: passes through (1, 1)
  3. Stretch vertically by 2: passes through (1, 2)
  4. Shift up 1: passes through (1, 3), asymptote y = 1

Example 2: Solve exponential

Solve 5^(x + 1) = 3^(2x - 1)

  1. Take log of both sides: (x + 1)ln(5) = (2x - 1)ln(3)
  2. x·ln(5) + ln(5) = 2x·ln(3) - ln(3)
  3. x·ln(5) - 2x·ln(3) = -ln(3) - ln(5)
  4. x(ln(5) - 2ln(3)) = -(ln(3) + ln(5))
  5. x = -(ln(3) + ln(5)) / (ln(5) - 2ln(3))
  6. x ≈ -(1.099 + 1.609) / (1.609 - 2.197) = -2.708 / (-0.588) ≈ 4.61


Quiz

Q1: What does the concept of Exponential Functions primarily refer to in this subject?

A) A historical anecdote about Exponential Functions B) A visual representation of Exponential Functions C) The definition and application of Exponential Functions D) A computational error related to Exponential Functions

Correct: C)

Q2: What is the primary purpose of Exponential Growth and Decay Models?

A) It is used to exponential growth and decay models in mathematical analysis B) It is used only in advanced research contexts C) It is primarily a historical notation system D) It replaces all other methods in this domain

Correct: A)

Q3: Which statement about Logarithm Laws is TRUE?

A) Logarithm Laws is an advanced topic beyond this subject's scope B) Logarithm Laws is mentioned only as a historical footnote C) Logarithm Laws is a fundamental concept covered in this subject D) Logarithm Laws is not related to this subject

Correct: C)

Q4: Based on the worked examples in this subject, what is the correct result?

A) 0, increasing, domain ℝ, range (0, ∞). B) An unrelated numerical value C) A different result from a common mistake D) The inverse of the correct answer

Correct: A)

Q5: How are Logarithm Laws and Logarithmic Functions related?

A) Logarithm Laws and Logarithmic Functions are completely unrelated topics B) Logarithm Laws is the inverse of Logarithmic Functions C) Logarithm Laws is a special case of Logarithmic Functions D) Logarithm Laws and Logarithmic Functions are closely related concepts

Correct: D)

Q6: What is a common pitfall when working with Solving Exponential Equations?

A) A common mistake is confusing Solving Exponential Equations with a similar concept B) Solving Exponential Equations has no common misconceptions C) The main error with Solving Exponential Equations is using it when it is not needed D) Solving Exponential Equations is always computed the same way in all contexts

Correct: A)

Q7: When should you apply Solving Logarithmic Equations?

A) Solving Logarithmic Equations is not practically useful B) Use Solving Logarithmic Equations only in pure mathematics contexts C) Avoid Solving Logarithmic Equations unless explicitly instructed D) Apply Solving Logarithmic Equations to solve problems in this subject's domain

Correct: D)

Practice Problems

  1. Graph features of y = 4ˣ Answer: Passes through (0, 1), asymptote y = 0, increasing, domain ℝ, range (0, ∞).

  2. Solve: log₃(x) = 4 Answer: x = 3⁴ = 81

  3. Solve: e^(2x) = 7 Answer: 2x = ln(7), x = ln(7)/2 ≈ 0.973

  4. Simplify: ln(8) - ln(2) Answer: ln(8/2) = ln(4)

  5. If P(t) = 100·e^(0.05t), what is P after 10 years? Answer: P(10) = 100·e^(0.5) ≈ 100 × 1.649 = 164.9


Summary

Key takeaways:

Pitfalls



Next Steps

Next up: 03-06-complex-numbers.md