00-06 — Powers and Roots
Phase: 0 — Arithmetic & Number Foundations Subject: 00-06 Prerequisites: 00-01 — Whole Number Arithmetic, 00-02 — Fractions, 00-03 — Decimals, 00-04 — Percentages, 00-05 — Integers and Directed Numbers Next subject: 00-07 — Ratios, Rates, and Proportions
Learning Objectives
By the end of this subject, you will be able to:
- Compute squares, cubes, and higher powers of integers and interpret index notation correctly
- Evaluate square roots and cube roots, including estimating roots that are not perfect squares/cubes
- Apply the five fundamental exponent laws (product, quotient, power of a power, power of a product, power of a quotient)
- Simplify expressions with zero, negative, and fractional exponents
- Understand why each exponent law works through concrete examples and derivations
Core Content
1. What Are Powers?
A power (or exponent) tells you how many times to multiply a number by itself.
aⁿ = a × a × a × ... × a (n times)
Where: - a is the base — the number being multiplied - n is the exponent (or index, or power) — how many copies are multiplied - aⁿ is read as "a to the power n" or "a to the nth power"
Examples: - 2³ = 2 × 2 × 2 = 8 (read "2 cubed" or "2 to the third power") - 5² = 5 × 5 = 25 (read "5 squared") - 10⁴ = 10 × 10 × 10 × 10 = 10,000
⚠️ THIS IS CRITICAL — Exponents appear everywhere in later mathematics: scientific notation, compound interest, exponential growth/decay, polynomials, logarithms, calculus, probability, and machine learning.
2. Squares and Square Roots
Squares
A square is a number raised to the power 2: n² = n × n.
The first few squares:
$0² = 0 1² = 1 2² = 4 3² = 9 4² = 16 5² = 25 6² = 36 7² = 49 8² = 64 9² = 81 10² = 100 11² = 121 12² = 144 13² = 169 14² = 196 15² = 225 $
Why are they called "squares"? Because n² gives the area of a square with side length n:
$ ┌─────────┐
│ │ 3
│ Area = │
│ 3² = 9 │
└─────────┘
3
$
Key properties of squares: - The square of any integer is always non-negative (positive or zero) - (−n)² = n² (negative numbers squared become positive) - Squares grow quickly: (2n)² = 4n² — doubling the base quadruples the square
Square Roots
The square root of a number x, written √x, is the non-negative number that, when squared, gives x.
√x = y means y² = x AND y ≥ 0
Examples: - √81 = 9 because 9² = 81 - √0 = 0 because 0² = 0 - √1 = 1 because 1² = 1
Why must the square root be non-negative? By convention, the √ symbol (called the principal square root or radical sign) always gives the non-negative root. The equation x² = 25 has TWO solutions (x = 5 or x = −5), but √25 = 5 only.
Important distinction: x² = 25 → x = ±5 (two solutions) But: √25 = 5 (one value, the principal root)
⚠️ THIS IS CRITICAL — The radical symbol √ always means the principal (non-negative) square root. This is one of the most common sources of errors in algebra.
Perfect squares are numbers whose square root is an integer: 0, 1, 4, 9, 16, 25, 36, 49, 64, 81, 100, 121, 144, ...
Estimating square roots of non-perfect squares:
For √50: since 7² = 49 and 8² = 64, we know √50 ≈ 7.07 (between 7 and 8, a bit above 7).
Negative numbers under the square root: √(−4) is NOT a real number. No real number squared gives a negative result. Square roots of negative numbers lead to imaginary numbers (covered in Phase 3).
3. Cubes and Cube Roots
Cubes
A cube is a number raised to the power 3: n³ = n × n × n.
$0³ = 0 1³ = 1 2³ = 8 3³ = 27 4³ = 64 5³ = 125 6³ = 216 7³ = 343 8³ = 512 9³ = 729 10³ = 1000 $
Why "cubes"? n³ gives the volume of a cube with side length n.
Key difference from squares: Cubes preserve the sign of the base. - (−2)³ = (−2) × (−2) × (−2) = 4 × (−2) = −8
With an odd exponent, negative bases stay negative.
Cube Roots
The cube root of x, written ∛x, is the number that when cubed gives x.
∛x = y means y³ = x
Examples: - ∛27 = 3 because 3³ = 27 - ∛(−27) = −3 because (−3)³ = −27 - ∛0 = 0
Unlike square roots, cube roots of negative numbers ARE real numbers because a negative number cubed IS negative.
4. Index Notation — General Powers
For any base a and positive integer exponent n:
aⁿ = a × a × ... × a (n factors)
Higher powers: - a⁴ = a × a × a × a (read "a to the fourth") - a¹⁰ = a multiplied by itself 10 times
Special conventions: - a¹ = a (by definition — one copy of a) - a⁰ = 1 for any a ≠ 0 (derived below in the exponent laws section)
5. Exponent Laws
⚠️ THIS IS CRITICAL — These five laws are the foundation for ALL work with exponents in algebra, calculus, and beyond. Memorize them and understand WHY they work.
Law 1: Product of Powers — aᵐ × aⁿ = a^(m+n)
Why it works:
aᵐ × aⁿ = (a × a × ... × a) × (a × a × ... × a) _ m factors __/ _ n factors __/ = a × a × ... × a (m + n factors total) = a^(m+n)
Example: 2³ × 2⁴ = 2^(3+4) = 2⁷ = 128 Check: 8 × 16 = 128 ✓
Common pitfall: aᵐ × aⁿ ≠ a^(m×n). The exponents ADD, not multiply. 2³ × 2⁴ = 2⁷, NOT 2¹².
Law 2: Quotient of Powers — aᵐ ÷ aⁿ = a^(m−n) (a ≠ 0)
Why it works:
aᵐ ÷ aⁿ = (a × a × ... × a) / (a × a × ... × a) = a × a × ... × a (m − n factors, after canceling n of them)
Example: 5⁷ ÷ 5⁴ = 5^(7−4) = 5³ = 125 Check: 78,125 ÷ 625 = 125 ✓
Law 3: Power of a Power — (aᵐ)ⁿ = a^(m×n)
Why it works:
(aᵐ)ⁿ = aᵐ × aᵐ × ... × aᵐ (n copies) = a^(m+m+...+m) (n times, by Law 1) = a^(m×n)
Example: (3²)⁴ = 3^(2×4) = 3⁸ = 6,561 Check: 3² = 9, 9⁴ = 9 × 9 × 9 × 9 = 6,561 ✓
Common pitfall: (aᵐ)ⁿ ≠ a^(mⁿ). 2^(3²) = 2⁹ = 512 is different from (2³)² = 2⁶ = 64.
Law 4: Power of a Product — (a × b)ⁿ = aⁿ × bⁿ
Why it works:
(a × b)ⁿ = (a × b) × (a × b) × ... × (a × b) (n factors) = (a × a × ... × a) × (b × b × ... × b) (rearrange) = aⁿ × bⁿ
Example: (2 × 5)³ = 2³ × 5³ = 8 × 125 = 1,000 Check: 10³ = 1,000 ✓
Common pitfall: (a + b)ⁿ ≠ aⁿ + bⁿ. For example, (2 + 3)² = 5² = 25, but 2² + 3² = 4 + 9 = 13. The power distributes over multiplication, NOT addition.
Law 5: Power of a Quotient — (a ÷ b)ⁿ = aⁿ ÷ bⁿ (b ≠ 0)
Why it works: The same reasoning as Law 4, but with division.
(a/b)ⁿ = (a/b) × (a/b) × ... × (a/b) = aⁿ / bⁿ
Example: (3/4)² = 3²/4² = 9/16 Check: (0.75)² = 0.5625 = 9/16 ✓
6. Zero Exponents — a⁰ = 1 (a ≠ 0)
Derivation from Law 2:
Consider aⁿ ÷ aⁿ. By Law 2: aⁿ ÷ aⁿ = a^(n−n) = a⁰. But any non-zero number divided by itself equals 1: aⁿ ÷ aⁿ = 1. Therefore: a⁰ = 1 (for a ≠ 0).
Examples: - 7⁰ = 1 - (−3)⁰ = 1 - (1000)⁰ = 1 - 0⁰ is undefined (it's an indeterminate form — you'll learn why in calculus)
7. Negative Exponents — a^(−n) = 1/aⁿ (a ≠ 0)
Derivation from Law 2:
Consider a⁰ ÷ aⁿ. By Law 2: a⁰ ÷ aⁿ = a^(0−n) = a^(−n). But a⁰ = 1, so 1 ÷ aⁿ = 1/aⁿ. Therefore: a^(−n) = 1/aⁿ.
Examples: - 2^(−3) = 1/2³ = 1/8 = 0.125 - 10^(−2) = 1/10² = 1/100 = 0.01 - (−4)^(−2) = 1/(−4)² = 1/16
Intuition: A negative exponent means "take the reciprocal." The exponent flips the base from numerator to denominator (or vice versa).
8. Fractional Exponents — a^(1/n) = ⁿ√a
Definition:
a^(1/n) = ⁿ√a (the nth root of a)
Why this makes sense with the exponent laws:
Consider (a^(1/n))ⁿ. By Law 3: (a^(1/n))ⁿ = a^((1/n)×n) = a¹ = a.
So a^(1/n) is the number that, when raised to the nth power, gives a — which is exactly the definition of the nth root.
Examples: - 9^(1/2) = √9 = 3 - 8^(1/3) = ∛8 = 2 - 32^(1/5) = 2 (because 2⁵ = 32) - 64^(1/6) = 2 (because 2⁶ = 64)
General fractional exponents: a^(m/n) = (ⁿ√a)^m = ⁿ√(a^m)
a^(m/n) = (a^(1/n))^m = (ⁿ√a)^m
Example: 8^(2/3) = (8^(1/3))² = 2² = 4 Alternatively: 8^(2/3) = (8²)^(1/3) = 64^(1/3) = 4
Both orderings work: - Root first then power: (ⁿ√a)^m (usually easier with numbers) - Power first then root: ⁿ√(a^m) (equivalent, same result)
Example: 27^(2/3)
Method 1 (root first): 27^(1/3) = 3, 3² = 9 Method 2 (power first): 27² = 729, 729^(1/3) = 9
Both give 9 ✓
Common pitfall: a^(m/n) ≠ a^m ÷ a^n. The fraction is IN the exponent, not a division problem! 8^(2/3) ≠ 8² ÷ 8³ = 64 ÷ 512 = 1/8.
9. Summary of All Exponent Rules
| Rule | Formula | When a ≠ 0 |
|---|---|---|
| Product | aᵐ × aⁿ = a^(m+n) | Always |
| Quotient | aᵐ ÷ aⁿ = a^(m−n) | a ≠ 0 |
| Power of power | (aᵐ)ⁿ = a^(m×n) | Always |
| Power of product | (ab)ⁿ = aⁿbⁿ | Always |
| Power of quotient | (a/b)ⁿ = aⁿ/bⁿ | b ≠ 0 |
| Zero exponent | a⁰ = 1 | a ≠ 0 |
| Negative exponent | a^(−n) = 1/aⁿ | a ≠ 0 |
| Fractional exponent | a^(m/n) = (ⁿ√a)^m | n ≠ 0 |
10. Common Misconceptions
Misconception 1: "√(a + b) = √a + √b" - Wrong! √(9 + 16) = √25 = 5, but √9 + √16 = 3 + 4 = 7 - Roots do NOT distribute over addition.
Misconception 2: "(a + b)² = a² + b²" - Wrong! (a + b)² = a² + 2ab + b² (you'll learn this in algebra) - (3 + 4)² = 7² = 49, but 3² + 4² = 9 + 16 = 25
Misconception 3: "−3² = (−3)² = 9" - Wrong! −3² = −(3²) = −9. The exponent applies to 3, not to the − sign. - This is an ORDER OF OPERATIONS issue: exponents before multiplication (the − is multiplication by −1).
Misconception 4: "a⁰ = 0" - Wrong! a⁰ = 1 for any a ≠ 0. Think: a³ ÷ a³ = a⁰ AND a³ ÷ a³ = 1, so a⁰ = 1.
Key Terms
- Cube Roots
- Cubes
- Perfect squares
- Powers
- Square Roots
- Square roots
- Squares
Worked Examples
Example 1: Simplifying with Exponent Laws
Simplify: (2³ × 2⁴ × 2²) ÷ 2⁶
Solution:
$(2³ × 2⁴ × 2²) ÷ 2⁶ = 2^(3+4+2) ÷ 2⁶ ← Law 1: add exponents of same base = 2⁹ ÷ 2⁶ = 2^(9−6) ← Law 2: subtract exponents = 2³ = 8 $
Answer: 8
Check by evaluating directly: 2³ = 8, 2⁴ = 16, 2² = 4, 2⁶ = 64 8 × 16 × 4 = 512 512 ÷ 64 = 8 ✓
Example 2: Negative and Fractional Exponents
Simplify and evaluate: 4^(−1/2) × 8^(2/3)
Solution:
$4^(−1/2) × 8^(2/3) $
Step 1 — Handle 4^(−1/2):
$4^(−1/2) = 1 / 4^(1/2) ← Negative exponent: reciprocal
= 1 / √4
= 1 / 2
$
Step 2 — Handle 8^(2/3):
$8^(2/3) = (8^(1/3))² ← Fractional: root first is easier
= 2² ← ∛8 = 2
= 4
$
Step 3 — Multiply:
$(1/2) × 4 = 2 $
Answer: 2
Example 3: Simplifying Complex Exponent Expressions
Simplify to a single power: ((5²)³ × 5⁴) / (5³)²
Solution:
$((5²)³ × 5⁴) / (5³)² = (5^(2×3) × 5⁴) / 5^(3×2) ← Law 3: (aᵐ)ⁿ = a^(m×n) = (5⁶ × 5⁴) / 5⁶ = 5^(6+4) / 5⁶ ← Law 1: product = 5¹⁰ / 5⁶ = 5^(10−6) ← Law 2: quotient = 5⁴ = 625 $
Answer: 5⁴ = 625
Example 4: Power of a Product with Fractional Expressions
Simplify: (27a³)^(1/3) assuming a > 0.
Solution:
$(27a³)^(1/3) = 27^(1/3) × (a³)^(1/3) ← Law 4: power distributes over product = ∛27 × a^(3 × 1/3) ← Law 3: power of power = 3 × a¹ ← ∛27 = 3, 3×1/3 = 1 = 3a $
Answer: 3a
Practice Problems
(Answers are below. Try each problem before checking.)
Problem 1: Evaluate: 3⁴ + 2³ − 5²
Problem 2: Simplify: 7⁵ × 7³ ÷ 7⁴
Problem 3: Evaluate: 16^(3/4)
Problem 4: Simplify: (2³)² × 2^(−4)
Problem 5: Evaluate: (−3)⁴ and −3⁴. Are they equal?
Problem 6: Simplify: (25a⁴b²)^(1/2) assuming a > 0, b > 0.
Problem 7: Evaluate: 9^(−1/2) + 27^(−1/3)
Problem 8: Simplify to a single number: ((2²)³ × 2^(−2)) / (2³)² × 2⁰
Answers (click to expand)
**Problem 1:** 3⁴ = 81, 2³ = 8, 5² = 25 81 + 8 − 25 = **64** **Problem 2:** 7⁵ × 7³ ÷ 7⁴ = 7^(5+3−4) = 7⁴ = **2,401** **Problem 3:** 16^(3/4) = (16^(1/4))³ = 2³ = **8** **Problem 4:** (2³)² × 2^(−4) = 2⁶ × 2^(−4) = 2^(6−4) = 2² = **4** **Problem 5:** (−3)⁴ = (−3) × (−3) × (−3) × (−3) = 9 × 9 = **81** −3⁴ = −(3⁴) = −81 **They are NOT equal.** The parentheses make all the difference. **Problem 6:** (25a⁴b²)^(1/2) = 25^(1/2) × (a⁴)^(1/2) × (b²)^(1/2) = 5 × a² × b¹ = **5a²b** **Problem 7:** 9^(−1/2) = 1/√9 = 1/3 27^(−1/3) = 1/∛27 = 1/3 1/3 + 1/3 = **2/3** **Problem 8:** ((2²)³ × 2^(−2)) / (2³)² × 2⁰ = (2⁶ × 2^(−2)) / 2⁶ × 1 = 2⁴ / 2⁶ = 2^(4−6) = 2^(−2) = **1/4**Summary
- Powers are repeated multiplication: aⁿ = a × a × ... × a (n times). The base a is multiplied n times.
- Square roots (√x) give the non-negative number whose square is x; cube roots (∛x) work for negative numbers too.
- Five fundamental exponent laws: (1) aᵐaⁿ = a^(m+n), (2) aᵐ/aⁿ = a^(m−n), (3) (aᵐ)ⁿ = a^(m×n), (4) (ab)ⁿ = aⁿbⁿ, (5) (a/b)ⁿ = aⁿ/bⁿ. These all follow from the definition of powers as repeated multiplication.
- Zero exponens: a⁰ = 1 (a ≠ 0). Negative exponents: a^(−n) = 1/aⁿ. Fractional exponents: a^(m/n) = (ⁿ√a)^m.
- ⚠️ Key pitfalls: exponents don't distribute over addition [(a+b)ⁿ ≠ aⁿ+bⁿ]; the radical symbol √ always means principal (non-negative) square root; −3² ≠ (−3)².
Pitfalls
- Assuming (a + b)ⁿ = aⁿ + bⁿ. Powers distribute over multiplication, NOT addition. (3 + 4)² = 7² = 49, but 3² + 4² = 9 + 16 = 25. This is the single most common exponent mistake and it persists through all of algebra.
- Thinking √(a + b) = √a + √b. Roots don't distribute over addition either. √(9 + 16) = √25 = 5, but √9 + √16 = 3 + 4 = 7.
- Confusing the product rule with the power-of-power rule. aᵐ × aⁿ = a^(m+n) (add exponents), but (aᵐ)ⁿ = a^(m×n) (multiply exponents). Swapping these produces answers that are off by orders of magnitude.
- Treating a⁰ as 0. For any non-zero a, a⁰ = 1. This follows from the quotient rule: aⁿ ÷ aⁿ = a^(n−n) = a⁰ = 1. Zero is only the result when multiplying by 0, not when the exponent is 0.
- Misreading the radical symbol √. √25 means the principal (non-negative) square root: √25 = 5 only, not ±5. The equation x² = 25 has two solutions (x = ±5), but the symbol √25 yields a single value by definition.
Quiz
Answer each question, then read the explanation for your choice.
Q1: Simplify: 2⁵ × 2³
A) 2¹⁵ B) 2⁸ C) 4⁸ D) 2²
Answer and Explanations
**Correct: B) 2⁸** By Law 1: 2⁵ × 2³ = 2^(5+3) = 2⁸. Exponents ADD when multiplying same base. - A) 2¹⁵: You multiplied exponents instead of adding. 2⁵ × 2³ ≠ 2^(5×3). - B) 2⁸: ✓ Correct. Add the exponents: 5 + 3 = 8. - C) 4⁸: You multiplied the bases AND added exponents incorrectly. The base stays the same. - D) 2²: You subtracted exponents instead of adding.Q2: Evaluate: 3⁴ ÷ 3²
A) 3⁸ B) 3² C) 9² D) 1²
Answer and Explanations
**Correct: B) 3²** By Law 2: 3⁴ ÷ 3² = 3^(4−2) = 3² = 9. - A) 3⁸: You added exponents instead of subtracting. Division means subtraction of exponents for the same base. - B) 3²: ✓ Correct. 3⁴ ÷ 3² = 3² = 9. Check: 81 ÷ 9 = 9 ✓ - C) 9²: You changed the base. 3⁴ = 81, not 9. The base stays as 3. - D) 1²: This equals 1. 81 ÷ 9 ≠ 1.Q3: What is (2³)⁴?
A) 2⁷ B) 2¹² C) 2⁸¹ D) 8⁴
Answer and Explanations
**Correct: B) 2¹²** By Law 3: (2³)⁴ = 2^(3×4) = 2¹² = 4,096. - A) 2⁷: You added the exponents (3 + 4) instead of multiplying. - B) 2¹²: ✓ Correct. Power of a power means multiply exponents. - C) 2⁸¹: You computed 3⁴ = 81 and kept it as the exponent. (aᵐ)ⁿ = a^(m×n), NOT a^(mⁿ). - D) 8⁴: This equals (2³)⁴ = 8⁴ = 4,096. This is a valid intermediate step, but the question asks to simplify to a single power of 2.Q4: Evaluate: 5⁰ × 3²
A) 0 B) 1 C) 9 D) 15
Answer and Explanations
**Correct: C) 9** 5⁰ = 1 (any non-zero number to the zero power is 1), and 3² = 9. So 1 × 9 = 9. - A) 0: You may have thought 5⁰ = 0. But a⁰ = 1 for any a ≠ 0. - B) 1: You stopped at 5⁰ = 1 without multiplying by 3². - C) 9: ✓ Correct. 5⁰ × 3² = 1 × 9 = 9. - D) 15: You may have computed 5⁰ = 5 and multiplied: 5 × 3 = 15. But 5⁰ = 1, not 5.Q5: Simplify: a³ × a⁵ / a²
A) a^(15/2) B) a⁶ C) a¹⁰ D) a⁰
Answer and Explanations
**Correct: B) a⁶** a³ × a⁵ / a² = a^(3+5) / a² = a⁸ / a² = a^(8−2) = a⁶ - A) a^(15/2): This would be the result of (a³ × a⁵)^(1/2), which is not what we have. - B) a⁶: ✓ Correct. Add exponents for product (3+5=8), subtract for division (8−2=6). - C) a¹⁰: You may have computed 3 × 5 − 2 = 13 or mishandled the operations. - D) a⁰: You may have subtracted all: 3 − 5 + 2 or similar mistake.Q6: What is 16^(3/4)?
A) 12 B) 8 C) 64 D) 4
Answer and Explanations
**Correct: B) 8** 16^(3/4) = (16^(1/4))³ = 2³ = 8 - A) 12: You may have done 16 × 3/4 = 12. But the exponent 3/4 does not mean multiply by 3/4. - B) 8: ✓ Correct. Fourth root of 16 is 2, then cube: 2³ = 8. - C) 64: You may have done 16^(3/4) = (16³)^(1/4) = 4096^(1/4) — which is actually also 8. 64 is 16³ with the 1/4 mishandled. - D) 4: You may have computed 16^(1/2) instead of 16^(3/4). Half of 3/4 ≠ 1/2.Q7: Which of the following equals a^(−2)?
A) 1/a² B) −a² C) a² D) −1/a²
Answer and Explanations
**Correct: A) 1/a²** By definition: a^(−n) = 1/aⁿ, so a^(−2) = 1/a². - A) 1/a²: ✓ Correct. The negative exponent means reciprocal. - B) −a²: The negative is in the exponent, not multiplying the result. a^(−2) ≠ −a². For example, 2^(−2) = 1/4 ≠ −4. - C) a²: Lost the negative sign. a^(−2) = 1/a² ≠ a². - D) −1/a²: The negative exponent gives a positive 1/a² (assuming a > 0), not negative 1/a².Q8: Evaluate: (−2)⁴ − 2⁴
A) −32 B) 0 C) 32 D) −16
Answer and Explanations
**Correct: B) 0** (−2)⁴ = (−2) × (−2) × (−2) × (−2) = 4 × 4 = 16 2⁴ = 16 16 − 16 = 0 - A) −32: You may have computed (−2)⁴ = −16 (treating it like −(2⁴)) and 2⁴ = 16, getting −32. - B) 0: ✓ Correct. Both equal 16, difference is zero. - C) 32: You may have computed (−2)⁴ = 16 and 2⁴ = 16 as 16 + 16 = 32. The operation is subtraction, not addition. - D) −16: You may have computed only (−2)⁴ − alone, or mishandled signs.Next Steps
Move on to 00-07 — Ratios, Rates, and Proportions to learn about ratio notation, simplifying ratios, direct and inverse proportion, unit rates, and scale factors.
Q5: Simplify: (a³)⁴ ÷ a⁵
A) a⁷ B) a¹² C) a² D) a
Answer: A) a⁷
(a³)⁴ = a^(3×4) = a¹². Then a¹² ÷ a⁵ = a^(12−5) = a⁷.