26-02 — Permutations

Phase: Combinatorics | Subject: 26-02 Prerequisites: 26-01-counting-principles.md Next subject: 26-03-combinations.md


Learning Objectives

By the end of this subject, you will be able to:

  1. Define a permutation as an ordered arrangement of distinct objects
  2. Compute $P(n, r) = \frac{n!}{(n-r)!}$ for permutations of $r$ from $n$
  3. Count permutations with repeated elements: $\frac{n!}{n_1! n_2! \ldots n_k!}$
  4. Solve circular permutation problems
  5. Apply permutations to probability and combinatorics problems

Core Content

Definition and Notation

A permutation is an ordered arrangement of objects. Distinct orderings of the same objects count as different permutations.

Factorial: $n! = n \times (n-1) \times (n-2) \times \cdots \times 2 \times 1$, with $0! = 1$.

Permutations of $n$ Distinct Objects

The number of ways to arrange $n$ distinct objects in a line is $n!$.

Example: Arrange letters A, B, C. $3! = 6$: ABC, ACB, BAC, BCA, CAB, CBA.

$r$-Permutations: $P(n, r)$

The number of ways to select and arrange $r$ objects from $n$ distinct objects (order matters):

$$P(n, r) = \frac{n!}{(n-r)!} = n \times (n-1) \times \cdots \times (n-r+1)$$

Derivation: $n$ choices for position 1, $(n-1)$ for position 2, ..., $(n-r+1)$ for position $r$. Multiply these $r$ terms.

Example: How many ways to award gold, silver, bronze from 10 athletes? $P(10, 3) = 10 \times 9 \times 8 = 720$.

Permutations with Repeated Elements

When some objects are identical, we overcount by the number of ways to rearrange the identical ones:

$$\frac{n!}{n_1! n_2! \ldots n_k!}$$

where $n_i$ is the number of copies of the $i$-th distinct element, and $\sum n_i = n$.

Example: Arrange the letters in MISSISSIPPI. Total: 11 letters. M=1, I=4, S=4, P=2. Count = $\frac{11!}{1!4!4!2!} = \frac{39,916,800}{1 \times 24 \times 24 \times 2} = \frac{39,916,800}{1152} = 34,650$.

Circular Permutations

Arranging $n$ distinct objects around a circle: $(n-1)!$ ways.

Reasoning: In a line, rotating everyone by one seat gives a different arrangement. Around a circle, rotations are considered the same. Fix one person to break symmetry, then arrange the remaining $n-1$ in $(n-1)!$ ways.

Example: Seat 5 people around a round table. $(5-1)! = 4! = 24$ arrangements.

⚠️ CRITICAL — If reflection is also considered identical (e.g., a necklace can be flipped), divide by 2: $\frac{(n-1)!}{2}$ for $n \geq 3$.

Permutations with Restrictions

Example: Arrange A, B, C, D where A and B sit together. Treat {A,B} as a block. Arrange 3 items (block, C, D): $3! = 6$. Arrange A and B within block: $2! = 2$. Total: $6 \times 2 = 12$.


Key Terms

Worked Examples

Example 1: $P(n, r)$ Calculation

Compute $P(12, 4)$.

Solution: $P(12, 4) = \frac{12!}{(12-4)!} = \frac{12!}{8!} = 12 \times 11 \times 10 \times 9 = 11,880$.

Click for answer $P(12, 4) = 11,880$. Only multiply the first 4 terms descending from 12.

Example 2: Repeated Letters

How many distinct arrangements of "BANANA"?

Solution: 6 letters: B=1, A=3, N=2. $\frac{6!}{1! 3! 2!} = \frac{720}{1 \times 6 \times 2} = \frac{720}{12} = 60$.

Click for answer 60 distinct arrangements.

Example 3: Circular with Constraint

In how many ways can 4 men and 4 women sit at a round table with men and women alternating?

Solution: Fix one man's seat (circular symmetry). The remaining 3 men fill every other seat (3! ways). The 4 women fill the 4 gaps (4! ways). Total: $3! \times 4! = 6 \times 24 = 144$.

Click for answer 144 alternating arrangements.


Quiz

Q1: What does the concept of Permutation primarily refer to in this subject?

A) A computational error related to Permutation B) A visual representation of Permutation C) A historical anecdote about Permutation D) The definition and application of Permutation

Correct: D)

Q2: Which of the following is the key formula discussed in this subject?

A) An unrelated formula from a different topic B) The inverse operation of the formula in question C) P(n, r) = \frac{n!}{(n-r)!} D) A simplified version of P(n, r) = \frac{n!}{(n-r)!}...

Correct: C)

Q3: What is the primary purpose of Factorial?

A) It is used to factorial in mathematical analysis B) It is used only in advanced research contexts C) It replaces all other methods in this domain D) It is primarily a historical notation system

Correct: A)

Q4: Which statement about Circular permutation is TRUE?

A) Circular permutation is a fundamental concept covered in this subject B) Circular permutation is an advanced topic beyond this subject's scope C) Circular permutation is mentioned only as a historical footnote D) Circular permutation is not related to this subject

Correct: A)

Q5: Based on the worked examples in this subject, what is the correct result?

A) Repeated Letters B) A different result from a common mistake C) An unrelated numerical value D) The inverse of the correct answer

Correct: A)

Q6: How are Circular permutation and Permutations with repetition related?

A) Circular permutation and Permutations with repetition are completely unrelated topics B) Circular permutation is a special case of Permutations with repetition C) Circular permutation is the inverse of Permutations with repetition D) Circular permutation and Permutations with repetition are closely related concepts

Correct: D)

Q7: What is a common pitfall when working with Definition And Notation?

A) Definition And Notation is always computed the same way in all contexts B) A common mistake is confusing Definition And Notation with a similar concept C) The main error with Definition And Notation is using it when it is not needed D) Definition And Notation has no common misconceptions

Correct: B)

Q8: When should you apply Permutations Of $N$ Distinct Objects?

A) Permutations Of $N$ Distinct Objects is not practically useful B) Use Permutations Of $N$ Distinct Objects only in pure mathematics contexts C) Avoid Permutations Of $N$ Distinct Objects unless explicitly instructed D) Apply Permutations Of $N$ Distinct Objects to solve problems in this subject's domain

Correct: D)

Practice Problems

  1. How many ways to arrange 7 books on a shelf?

    Click for answer $7! = 5040$.

  2. From 15 runners, how many ways can the top 4 positions (1st-4th) be filled?

    Click for answer $P(15, 4) = 15 \times 14 \times 13 \times 12 = 32,760$.

  3. How many distinct arrangements of "MISSISSIPPI"?

    Click for answer $11!/(4!4!2!) = 34,650$.

  4. Seat 6 people around a circular table. How many arrangements?

    Click for answer $(6-1)! = 5! = 120$.

  5. Arrange 5 students where Alice and Bob must sit together. How many ways?

    Click for answer Treat {Alice, Bob} as a block: 4 items → $4!$. Permute within block: $2!$. Total: $24 \times 2 = 48$.


Summary

Key takeaways:


Pitfalls



Next Steps

Next up: 26-03-combinations.md — unordered selections, binomial coefficients, and the relationship between permutations and combinations.