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04-09 - L'Hôpital's Rule

Phase: 4 | Subject: 04-09 Prerequisites: 04-01-limits.md (indeterminate forms), 04-05-derivatives-of-elementary-functions.md Next subject: 04-10-newtons-method.md


Learning Objectives

By the end of this subject, you will be able to:

  1. Recognise indeterminate forms 0/0 and ∞/∞
  2. Apply L'Hôpital's Rule
  3. Handle repeated applications of L'Hôpital's Rule
  4. Deal with other indeterminate forms (0·∞, ∞-∞, 0⁰, 1^∞, ∞⁰)

Core Content

Indeterminate Forms

When evaluating limits, direct substitution may give: - 0/0 - ∞/∞ - 0·∞ - ∞ - ∞ - 0⁰, 1^∞, ∞⁰

These are NOT actual values — they're "competitions" between functions.

L'Hôpital's Rule

⚠️ THIS IS CRITICAL — L'Hôpital's Rule is a powerful shortcut, but ONLY for 0/0 or ∞/∞ forms. Do NOT apply it to limits that are not indeterminate, and always check that f' and g' exist near a with g'(x) ≠ 0.

If $lim(x→a)$ f(x) = 0 and $lim(x→a)$ g(x) = 0 (0/0 form), OR both limits are ±∞ (∞/∞ form):

$$lim(x→a)$ f(x)/g(x) = $lim(x→a)$ f'(x)/g'(x)
$

Provided the limit on the right exists (or is ±∞).

Key: Differentiate NUMERATOR and DENOMINATOR SEPARATELY. Not the quotient rule!

Example: $lim(x→0)$ sin(x)/x 0/0 form. Apply L'Hôpital: = $lim(x→0)$ cos(x)/1 = 1/1 = 1

Example: $lim(x→∞)$ x/eˣ ∞/∞ form. Apply L'Hôpital: = $lim(x→∞)$ 1/eˣ = 0

Repeated Applications

Sometimes one application still gives 0/0 or ∞/∞.

Example: $lim(x→0)$ (sin(x) - x)/x³ First: (cos(x) - 1)/(3x²) → 0/0 Second: (-sin(x))/(6x) → 0/0 Third: (-cos(x))/6 → -1/6

Other Indeterminate Forms

0·∞

Rewrite as a fraction: 0·∞ = 0/(1/∞) or ∞/(1/0)

Example: $lim(x→0⁺)$ x·ln(x) = $lim(x→0⁺)$ ln(x)/(1/x) = (-∞)/(∞) Apply L'Hôpital: (1/x)/(-1/x²) = -x → 0

∞ - ∞

Combine into a single fraction.

Example: $lim(x→∞)$ (√(x² + x) - x) = $lim(x→∞)$ (√(x² + x) - x)(√(x² + x) + x)/(√(x² + x) + x) = $lim(x→∞)$ x/(√(x² + x) + x) = $lim(x→∞)$ 1/(√(1 + 1/x) + 1) = 1/2

Exponential forms (0⁰, 1^∞, ∞⁰)

Take natural log first.

Example: $lim(x→0⁺)$ xˣ Let y = xˣ, so ln(y) = x·ln(x) $lim(x→0⁺)$ x·ln(x) = $lim(x→0⁺)$ ln(x)/(1/x) = (-∞)/(∞) L'Hôpital: (1/x)/(-1/x²) = -x → 0 So ln(y) → 0, meaning y → e⁰ = 1



Key Terms

Worked Examples

Example 1: Basic L'Hôpital

$lim(x→0)$ (eˣ - 1)/x 0/0 form. L'Hôpital: eˣ/1 → 1/1 = 1

Example 2: Repeated

$lim(x→0)$ (1 - cos(x))/x² 0/0. First: sin(x)/(2x) → 0/0. Second: cos(x)/2 → 1/2

Example 3: ∞ - ∞

$lim(x→0)$ (1/x - 1/sin(x)) Direct: ∞ - ∞.

Combine: = $lim(x→0)$ (sin(x) - x)/(x·sin(x)) → 0/0 L'Hôpital: $lim(x→0)$ (cos(x) - 1)/(sin(x) + x·cos(x)) → 0/0 Second: $lim(x→0)$ (-sin(x))/(cos(x) + cos(x) - x·sin(x)) = $lim(x→0)$ (-sin(x))/(2cos(x) - x·sin(x)) = 0/(2) = 0



Quiz

Q1: What does the concept of Indeterminate Forms primarily refer to in this subject?

A) A computational error related to Indeterminate Forms B) A historical anecdote about Indeterminate Forms C) The definition and application of Indeterminate Forms D) A visual representation of Indeterminate Forms

Correct: C)

Q2: What is the primary purpose of Other Indeterminate Forms?

A) It is used only in advanced research contexts B) It replaces all other methods in this domain C) It is used to other indeterminate forms in mathematical analysis D) It is primarily a historical notation system

Correct: C)

Q3: Which statement about Repeated Applications is TRUE?

A) Repeated Applications is an advanced topic beyond this subject's scope B) Repeated Applications is a fundamental concept covered in this subject C) Repeated Applications is mentioned only as a historical footnote D) Repeated Applications is not related to this subject

Correct: B)

Q4: Based on the worked examples in this subject, what is the correct result?

A) The inverse of the correct answer B) An unrelated numerical value C) A different result from a common mistake D) 2.

Correct: D)

Q5: How are Repeated Applications and L'Hôpital'S Rule related?

A) Repeated Applications and L'Hôpital'S Rule are completely unrelated topics B) Repeated Applications and L'Hôpital'S Rule are closely related concepts C) Repeated Applications is a special case of L'Hôpital'S Rule D) Repeated Applications is the inverse of L'Hôpital'S Rule

Correct: B)

Q6: What is a common pitfall when working with ∞ - ∞?

A) ∞ - ∞ is always computed the same way in all contexts B) The main error with ∞ - ∞ is using it when it is not needed C) A common mistake is confusing ∞ - ∞ with a similar concept D) ∞ - ∞ has no common misconceptions

Correct: C)

Q7: When should you apply Exponential Forms (0⁰, 1^∞, ∞⁰)?

A) Avoid Exponential Forms (0⁰, 1^∞, ∞⁰) unless explicitly instructed B) Use Exponential Forms (0⁰, 1^∞, ∞⁰) only in pure mathematics contexts C) Exponential Forms (0⁰, 1^∞, ∞⁰) is not practically useful D) Apply Exponential Forms (0⁰, 1^∞, ∞⁰) to solve problems in this subject's domain

Correct: D)

Practice Problems

  1. $lim(x→0)$ sin(2x)/x Answer: L'Hôpital: 2cos(2x)/1 → 2. Or use sin(2x) ≈ 2x, so limit = 2.

  2. $lim(x→∞)$ ln(x)/x Answer: L'Hôpital: (1/x)/1 = 0.

  3. $lim(x→0⁺)$ x·ln(x) Answer: Rewrite as ln(x)/(1/x). L'Hôpital: (1/x)/(-1/x²) = -x → 0.

  4. $lim(x→0)$ (eˣ - 1 - x)/x² Answer: 0/0. First: (eˣ - 1)/(2x) → 0/0. Second: eˣ/2 → 1/2.

  5. $lim(x→∞)$ (1 + 1/x)ˣ Answer: Let y = (1 + 1/x)ˣ. ln(y) = x·ln(1 + 1/x) = ln(1 + 1/x)/(1/x). L'Hôpital: (1/(1+1/x)·(-1/x²))/(-1/x²) = 1/(1+1/x) → 1. So y → e¹ = e.


Summary

Key takeaways:


Pitfalls



Next Steps

Next up: 04-10-newtons-method.md