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02-03 - Polygons and Circles

Phase: 2 | Subject: 02-03 Prerequisites: 02-02-triangles.md (angle sums, basic geometry) Next subject: 02-04-perimeter-area-volume.md


Learning Objectives

By the end of this subject, you will be able to:

  1. Calculate interior and exterior angles of regular polygons
  2. Classify and understand properties of common quadrilaterals
  3. Calculate circumference and area of circles
  4. Calculate arc length and sector area
  5. Apply circle terminology correctly

Core Content

Polygons

A polygon is a closed 2D shape with straight sides. Named by the number of sides:

Sides Name
3 Triangle
4 Quadrilateral
5 Pentagon
6 Hexagon
7 Heptagon
8 Octagon
n n-gon

Interior Angles

⚠️ THIS IS CRITICAL — the formula (n-2)×180° lets you find the angle sum of ANY polygon. Trigonometric functions, tiling, and 3D geometry all depend on this.

Sum of interior angles: $(n - 2) × 180°$ where n = number of sides

Example: Hexagon (n = 6) Sum = (6 - 2) × 180° = 4 × 180° = 720°

Each interior angle of a regular polygon: $(n - 2) × 180° / n$

Example: Regular pentagon (n = 5) Each angle = (3 × 180°) / 5 = 540° / 5 = 108°

Exterior Angles

An exterior angle is formed by extending one side.

Key fact: The sum of exterior angles of ANY polygon is always 360° (one full revolution).

Each exterior angle of a regular polygon: $360° / n$

Example: Regular octagon (n = 8) Each exterior angle = 360° / 8 = 45°

Relationship: Interior + Exterior = 180° (they form a straight line)

Quadrilaterals

Parallelogram

Rectangle

Rhombus

Square

Trapezium (US: Trapezoid)

Kite

Circle Terminology

Term Definition
Centre The middle point of the circle
Radius (r) Distance from centre to edge
Diameter (d) Distance across through centre: d = 2r
Circumference Distance around the circle
Chord Line segment connecting two points on the circle
Tangent Line touching the circle at exactly one point
Secant Line intersecting the circle at two points
Arc Part of the circumference
Sector "Pizza slice" — bounded by two radii and an arc
Segment Region bounded by a chord and an arc
Pi (π) Ratio of circumference to diameter: π ≈ 3.14159...

Circumference and Area

⚠️ THIS IS CRITICAL — C = 2πr and A = πr² are the two most important circle formulas. π and the circle appear in trigonometry, calculus, complex numbers, Fourier analysis, and normal distributions.

$Circumference: C = 2πr = πd
Area: A = πr²
$

Example: Circle with radius 5 - Circumference: C = 2π(5) = 10π ≈ 31.42 - Area: A = π(25) = 25π ≈ 78.54

Arc Length

$Arc length = (θ/360°) × 2πr
$

where θ = central angle in degrees

Example: Arc with central angle 60° in circle of radius 6 Arc length = (60/360) × 2π(6) = (1/6) × 12π = 2π ≈ 6.28

Sector Area

$Sector area = (θ/360°) × πr²
$

Example: Sector with central angle 90° in circle of radius 4 Sector area = (90/360) × π(16) = (1/4) × 16π = 4π ≈ 12.57

Segment Area

Area of segment = Area of sector - Area of triangle

Example: Segment with central angle 60° in circle of radius 6 - Sector area: (60/360) × π(36) = 6π - Triangle area (equilateral!): (√3/4) × 6² = 9√3 - Segment area: 6π - 9√3 ≈ 18.85 - 15.59 = 3.26



Key Terms

Worked Examples

Example 1: Regular decagon (10 sides)

  1. Each exterior angle: 360° / 10 = 36°
  2. Each interior angle: 180° - 36° = 144°
  3. Sum of interior angles: (10-2) × 180° = 8 × 180° = 1440°

Example 2: Circle with diameter 10

  1. Radius: r = 5
  2. Circumference: C = πd = 10π ≈ 31.42
  3. Area: A = πr² = 25π ≈ 78.54

Example 3: Sector with radius 8 and angle 45°

  1. Arc length: (45/360) × 2π(8) = (1/8) × 16π = 2π ≈ 6.28
  2. Sector area: (45/360) × π(64) = (1/8) × 64π = 8π ≈ 25.13


Quiz

Q1: What does the concept of Arc Length primarily refer to in this subject?

A) The definition and application of Arc Length B) A visual representation of Arc Length C) A computational error related to Arc Length D) A historical anecdote about Arc Length

Correct: A)

Q2: What is the primary purpose of Centre?

A) It is used to centre in mathematical analysis B) It is primarily a historical notation system C) It is used only in advanced research contexts D) It replaces all other methods in this domain

Correct: A)

Q3: Which statement about Chord is TRUE?

A) Chord is a fundamental concept covered in this subject B) Chord is mentioned only as a historical footnote C) Chord is an advanced topic beyond this subject's scope D) Chord is not related to this subject

Correct: A)

Q4: Based on the worked examples in this subject, what is the correct result?

A) The inverse of the correct answer B) 900° C) An unrelated numerical value D) A different result from a common mistake

Correct: B)

Q5: How are Chord and Circle Terminology related?

A) Chord and Circle Terminology are closely related concepts B) Chord is the inverse of Circle Terminology C) Chord is a special case of Circle Terminology D) Chord and Circle Terminology are completely unrelated topics

Correct: A)

Q6: What is a common pitfall when working with Circumference?

A) The main error with Circumference is using it when it is not needed B) Circumference has no common misconceptions C) A common mistake is confusing Circumference with a similar concept D) Circumference is always computed the same way in all contexts

Correct: C)

Q7: When should you apply Circumference and Area?

A) Circumference and Area is not practically useful B) Avoid Circumference and Area unless explicitly instructed C) Apply Circumference and Area to solve problems in this subject's domain D) Use Circumference and Area only in pure mathematics contexts

Correct: C)

Practice Problems

  1. Sum of interior angles of a heptagon (7 sides) Answer: (7-2) × 180° = 5 × 180° = 900°

  2. Each exterior angle of a regular 12-sided polygon Answer: 360° / 12 = 30°

  3. Each interior angle of a regular hexagon Answer: (6-2) × 180° / 6 = 720° / 6 = 120°

  4. Circumference of circle with radius 7 Answer: C = 2π(7) = 14π ≈ 43.98

  5. Area of circle with diameter 12 Answer: r = 6, A = π(36) = 36π ≈ 113.10

  6. Arc length with radius 10 and angle 72° Answer: (72/360) × 2π(10) = (1/5) × 20π = 4π ≈ 12.57

  7. Sector area with radius 6 and angle 120° Answer: (120/360) × π(36) = (1/3) × 36π = 12π ≈ 37.70


Summary

Key takeaways:


Pitfalls



Next Steps

Next up: 02-04-perimeter-area-volume.md